Answer:
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Answer:
0.66 m/s²
Explanation:
The following data were obtained from the question:
Initial velocity (u) = 0
Final velocity (v) = 5.4 m/s
Time (t) = 8.2 secs
Acceleration (a) =....?
The acceleration of the dog can be obtained as follow:
v = u + at
5.4 = 0 + a × 8.2
5.4 = 8.2a
Divide both side 8.2
a = 5.4/8.2
a = 0.66 m/s²
Therefore, the acceleration of the dog is 0.66 m/s².
At t =0, the velocity of A is greater than the velocity of B.
We are told in the question that the spacecrafts fly parallel to each other and that for the both spacecrafts, the velocities are described as follows;
A: vA (t) = ť^2 – 5t + 20
B: vB (t) = t^2+ 3t + 10
Given that t = 0 in both cases;
vA (0) = 0^2 – 5(0) + 20
vA = 20 m/s
For vB
vB (0) = 0^2+ 3(0) + 10
vB = 10 m/s
We can see that at t =0, the velocity of A is greater than the velocity of B.
Learn more: brainly.com/question/24857760
Read each question carefully. Show all your work for each part of the question. The parts within the question may not have equal weight. Spacecrafts A and B are flying parallel to each other through space and are next to each other at time t= 0. For the interval 0 <t< 6 s, spacecraft A's velocity v A and spacecraft B's velocity vB as functions of t are given by the equations va (t) = ť^2 – 5t + 20 and VB (t) = t^2+ 3t + 10, respectively, where both velocities are in units of meters per second. At t = 6 s, the spacecrafts both turn off their engines and travel at a constant speed. (a) At t = 0, is the speed of spacecraft A greater than, less than, or equal to the speed of spacecraft B?
The formula of net Force is:
F = ma
where m is the mass of the object
a is the acceleration of the object
so if we triple the net force applied to the object:
3F = ma
a = 3F / m
so the acceleration will also be tripled. because from the equation, the force is directly proportional to the acceleration