1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Marysya12 [62]
3 years ago
11

A brick is dropped from 100m up. Find it's impact velocity and air time.

Physics
1 answer:
ivann1987 [24]3 years ago
4 0
The airtime is 9.8
the velocity is 0
You might be interested in
A person is filling a knee-high bucket with water using a garden hose and holding it such that water discharges from the hose at
Serggg [28]

Answer:

Yes i am agree with this suggestion

Explanation:

Given that we have to assume that there is no any frictional affects.

As we know that when height increases then the discharge level will decreases when discharge level decreases then the time of filling for the bucket will increase.So the  bucket will fill faster if the hose lowered until knee level.

Yes i am agree with this suggestion

8 0
3 years ago
A particle of charge 2.0 x 10^-8C experiences an upward force of magnitude 4.0 x10^-6 when it is placed in a particular point in
koban [17]

Answer:

a) The electric field at that point is 2.0\times 10^{2} newtons per coulomb.

b) The electric force is 2.0\times 10^{-6} newtons.

Explanation:

a) Let suppose that electric field is uniform, then the following electric field can be applied:

E = \frac{F_{e}}{q} (1)

Where:

E - Electric field, measured in newtons per coulomb.

F_{e} - Electric force, measured in newtons.

q - Electric charge, measured in coulombs.

If we know that F_{e} = 4.0\times 10^{-6}\,N and q = 2.0\times 10^{-8}\,C, then the electric field at that point is:

E = \frac{4.0\times 10^{-6}\,N}{2.0\times 10^{-8}\,C}

E = 2.0\times 10^{2}\,\frac{N}{C}

The electric field at that point is 2.0\times 10^{2} newtons per coulomb.

b) If we know that E = 2.0\times 10^{2}\,\frac{N}{C} and q = 1.0\times 10^{-8}\,C, then the electric force is:

F_{e} = E\cdot q

F_{e} = \left(2.0\times 10^{2}\,\frac{N}{C} \right)\cdot (1.0\times 10^{-8}\,C)

F_{e} = 2.0\times 10^{-6}\,N

The electric force is 2.0\times 10^{-6} newtons.

7 0
3 years ago
A fixed electric space heater wired by a cable with an ampacity of 30 A should draw a maximum current of A. 30 A. B. 24 A. C. 15
Nookie1986 [14]

Answer: The correct answer is option (A).

Explanation

Ampacity is defined as the maximum amount of the current carried by the conductor continuously without exceeding its temperature rating.

The ampacity of the wire of the heater is 30 A .And this means that wire is capable of conducting current of maximum amount of 30 Ampere through it without exceeding its temperature rating.

Hence, the correct answer is option is (A).

7 0
3 years ago
What is the voltage in an electric current?
k0ka [10]
It is the energy of the electrons I believe
5 0
3 years ago
A worker wants to load some bricks in to his van. there are 1000 bricks and when stacked neatly they measure 2m by 1m by 1m, wha
inessss [21]

lenddbisnwjw whwjwiwnww

8 0
2 years ago
Other questions:
  • I need homework help
    10·1 answer
  • 1) The smallest part of an element that behaves like the element is the atom.
    7·1 answer
  • Helppppp pleaseeeee!!!!!!!
    14·2 answers
  • 33 POINTS How can I get the temperature? SOUND SPEED 340 m/s = 331 m/s + (0,6xTemperature)
    14·1 answer
  • Why do you see colors when you look at reflected light from a cd
    12·1 answer
  • How are Neptune and Uranus allke?
    8·2 answers
  • PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!<br><br> The two main types of circuits are:
    8·1 answer
  • Question 3 of 10
    8·2 answers
  • The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is 14900 N and acts as shown i
    8·1 answer
  • What speed should a satellite of mass 4,900 kg moving around
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!