Answer:
the work done by the motor is 531,45 Joules
Explanation:
Using a sketch of the possible conditions, we need to find the distance that the block was moved, in order to find the work done by the electrical motor.
The sketch could be seen in the attached image.
Answer:
1.603 s
Explanation:
Given that
Initial mass, = 0.45 kg
Initial period, = 1.45 s
Initial radius, = 0.14 m
Final mass, = 0.55 kg
Final period, = ?
Final radios, = 0.14 m
Since we are finding the rotation period of two masses of same radius, we can assume that the outward force is the same in both cases. This means that
m₁r₁ω₁² = m₂r₂ω2²
Where, ω = 2π/T, on substituting, we have
0.45 * 0.14 * (2π / 1.45)² = 0.550 * 0.14 * (2π / T₂)²
0.45 / 1.45² = 0.550 / T₂²
T₂² = 0.550 * 1.45² / 0.45
T₂² = 2.56972
T₂ = √2.56972
T₂ = 1.603 sec
Answer:
3.78075x10^6 kg x meter^2/ second^2
Explanation:
Kinetic energy K= 1/2 x mass x velocity^2
Neutral charge, because neutron means neutral
<span>If u want only WHether the total resistance is
less than 2 or less than 5 or more than 5 ohms: there is a Simple way.
When you connect resistances in parallel, resultant resistance is always
smaller than all of them. So it is less than 2 ohms</span>.
