All categories

2 years ago

Find minimum value for the perimeter of the rectangle.

Mathematics

1 answer:

katrin [286]2 years ago

7 0

Answer:

possible lengths

45 and 2

3 and 20

5 and 18

15 and 6

10 and 9

there perimeter will be

answer to this question is 15 and 6

You might be interested in

Which equation represents a proportional relationship? A) y = 3x 8 B) y = 3 8x C) y = 3x 8 + 1 D) y = 3 8x + 1

miskamm [114]

Answer: The answer is ¨B¨

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which shows the expressions in the order they would appear on a number line from least to greatest?

Illusion [34]

<span>c.)11 over 9, square root of 5, square root of 11, square root of 20, 2 to the power of 3

In order to compare, try to bring all of them into one similar form, like decimal.
Then, 11/9 = 1.22
Then, we can compare numbers under root, as 5 would be smaller than 11 which in turn is smaller than the 20, then 2^3 is 8, largest in series.

Hope this helps!</span>

6 0

2 years ago

Read 2 more answers

Which statement is true about the equation 2(4x + 10) = 8x + 12? A. The equation has only one solution, x = 8. B. The equation h

Amiraneli [1.4K]

Answer:

Please view this i think that is C

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

In a game of poker a hand of five cards is dealt to each player from a deck of 52 cards. find the probablility of a hand contain

aalyn [17]

Answer:

0.00597

Step-by-step explanation:

Given,

Total number of cards = 52,

In which flush cards = 20,

Also, the number of spade flush cards = 5,

Since,

$\text{Probability}=\frac{\text{Favourable outcomes}}{\text{Total outcomes}}$

Thus, the probability of a hand containing a spade flush, if each player has 5 cards

$=\frac{\text{Ways of selecting a spade flush card}}{\text{Total ways of selecting five cards}}$

$=\frac{^{20}C_5}{^{52}C_5}$

$=\frac{\frac{20!}{5!15!}}{\frac{52!}{5!47!}}$

$=\frac{15504}{2598960}$

= 0.00597

7 0

3 years ago

The sum of first three terms of a finite geometric series is -7/10 and their product is -1/125. [Hint: Use a/r, a, and ar to rep

Alchen [17]

Ooh, fun

geometric sequences can be represented as
$a_n=a(r)^{n-1}$
so the first 3 terms are
$a_1=a$
$a_2=a(r)$
$a_2=a(r)^2$

the sum is -7/10
$\frac{-7}{10}=a+ar+ar^2$
and their product is -1/125
$\frac{-1}{125}=(a)(ar)(ar^2)=a^3r^3=(ar)^3$

from the 2nd equation we can take the cube root of both sides to get
$\frac{-1}{5}=ar$
note that a=ar/r and ar²=(ar)r
so now rewrite 1st equation as
$\frac{-7}{10}=\frac{ar}{r}+ar+(ar)r$
subsituting -1/5 for ar
$\frac{-7}{10}=\frac{\frac{-1}{5}}{r}+\frac{-1}{5}+(\frac{-1}{5})r$
which simplifies to
$\frac{-7}{10}=\frac{-1}{5r}+\frac{-1}{5}+\frac{-r}{5}$
multiply both sides by 10r
-7r=-2-2r-2r²
add (2r²+2r+2) to both sides
2r²-5r+2=0
solve using quadratic formula
for $ax^2+bx+c=0$
$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}$
so
for 2r²-5r+2=0
a=2
b=-5
c=2

$r=\frac{-(-5) \pm \sqrt{(-5)^2-4(2)(2)}}{2(2)}$
$r=\frac{5 \pm \sqrt{25-16}}{4}$
$r=\frac{5 \pm \sqrt{9}}{4}$
$r=\frac{5 \pm 3}{4}$
so
$r=\frac{5+3}{4}=\frac{8}{4}=2$ or $r=\frac{5-3}{4}=\frac{2}{4}=\frac{1}{2}$

use them to solve for the value of a
$\frac{-1}{5}=ar$
$\frac{-1}{5r}=a$
try for r=2 and 1/2
$a=\frac{-1}{10}$ or $a=\frac{-2}{5}$

test each
for a=-1/10 and r=2
a+ar+ar²= $\frac{-1}{10}+\frac{-2}{10}+\frac{-4}{10}=\frac{-7}{10}$
it works

for a=-2/5 and r=1/2
a+ar+ar²= $\frac{-2}{5}+\frac{-1}{5}+\frac{-1}{10}=\frac{-7}{10}$
it works

both have the same terms but one is simplified

the 3 numbers are $\frac{-2}{5}$ , $\frac{-1}{5}$ , and $\frac{-1}{10}$

6 0

3 years ago

Find minimum value for the perimeter of the rectangle.​

Find minimum value for the perimeter of the rectangle.