Answer:
Microsoft will choses High price and you will choose to enter the market .
Explanation:
The Nash equilibrium
<u> You </u>
<u> enter Don't enter</u>
Microsoft high price ( $30 , $10 ) ( $60 , $0 )
Microsoft low price ( $20, -$5 ) ( $50, $0 )
From the Nash equilibrium the best time for you to enter the market is when Microsoft Charges a high price
While the best time for Microsoft is when it charges a high price and you do not enter the market
But considering Simultaneous Move game : Microsoft will choses High price and you will choose to enter the market .
Answer:
demand of
Fall
decrease
Explanation:
Here are the options to this question:
1.expect the (supply of/ demand of )
2.forecasters to (increase/ decrease)
3. weather forecasters to (decrease/ increase)
The new technology would reduce the need for weather forecasters. So t.v. stations and radios would no longer employ weather forecasters and might even lay off some forecasters. So the demand for forecasters would fall.
Due to the reduced demand for forecasters, there would be a large number of unemployed forecasters with no one willing to employ them. This would lead them to a reduction in their salary. When supply exceeds demand, prices fall.
I hope my answer helps you
Answer: Marketing Strategy
Explanation: Marketing strategies are additional benefit a business owner creates in its business to make it different from others in the same industry and to make prospective clients permanent customers.
Marketing strategies gives the business a better edge in its industry as it gives the business better sales.
Answer:
Following is the solution for the given problem.
Explanation:
Best order size, EOQ =√2DS/H
EOQ = √2*4700*60/5
EOQ = 336 units.
D = 4700/300 = 15.66.
σ L= √∑σ²
= √3*(5)² = 8.66.
Reorder point, R = D*L+ z σ L
Reorder point, R = 15.66*3 + 1.282*8.66
Reorder point, R = 58 units.
Suppose GetThere Airlines increases their ticket price to $200+10n = 10(20+n)$ dollars. Then the number of tickets they sell is $40,000-1000n = 1000(40-n)$ .<span> Therefore, their total revenue is
</span>
$$10(20+n)\cdot 1000(40-n) = 10000(20+n)(40-n) = 10000(800+20n-n^2).$$
This is maximized when $n=-\left(\frac{20}{2\cdot(-1)}\right)=10$ .<span> Therefore, they should charge </span><span>$200+10\cdot 10 = \boxed{300}$</span><span> dollars per ticket.</span>