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Alenkasestr [34]
3 years ago
8

What's the area of this

Mathematics
1 answer:
denis-greek [22]3 years ago
3 0

Answer:

133

Step-by-step explanation:

Because the figure is an irregular figure we need to break it up into two regular figures

The figure would be broken into..

A square with a side length of 4

And a rectangle with a length 13 and a width of 9

We now find the areas of the regular figures and add them together to get our answer

For the square.

To find the area of a square simply square the side length

Area = 4^2 = 16

For the rectangle

to find the area of the rectangle simply multiply the Length by the width

Area = 13*9= 117

Finally add the two areas together to get the area of the composite figure

117 + 16 = 133

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A, C, B, B, D, C here you goo
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Can someone please help first answer gets brainlist
OLga [1]

Answer:

3/5

Step-by-step explanation:

0.6 is actually 6/10 as a fraction. You divide bot the 6 and the 10 by 2 to get 3/5

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Of the total number of spectators at a circus show, 1/4 are men. 2/5 of the remaining number of spectators are women. There are
ch4aika [34]

Answer: There are 198 children at the circus show.

Step-by-step explanation:

Let be "x" the total number of spectators at the circus show and "c" the number of children at the circus show.

Knowing that \frac{1}{4} of the spectators are men, we can find the remaining:

x-\frac{1}{4}x=\frac{3}{4}x

Since \frac{2}{5} of the remaining number of spectaros are women and there are a total of 132 women, we can write the following equation:

(\frac{2}{5})(\frac{3}{4}x)=132

Solving for "x", we get:

x=(132)(\frac{20}{6})\\\\x=440

Therefore, we get that "c" is:

 c=440-\frac{1}{4}(440)-132\\\\c=198

8 0
3 years ago
The resquest of the y'+6y=e^4t, y(0)=2
kotegsom [21]
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x). 
<span>Multiplying both sides of the equation by the integrating factor: </span>

<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>

<span>The left side is the derivative of ye^(6x), hence </span>

<span>d/dx[ye^(6x)] = e^(12x) </span>

<span>Integrating </span>

<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>

<span>y = (1/12)e^(6x) + ce^(-6x) </span>

<span>Use the initial condition y(0)=-8 to find c: </span>

<span>-8 = (1/12) + c </span>
<span>c=-97/12 </span>

<span>Hence </span>

<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
7 0
3 years ago
Make a frequency distribution and find the relative frequencies for the following number set. Round the relative frequency to th
Mandarinka [93]
Number......frequency.....relative frequency
10                  2                    2/24 = 8.3%
20                  2                    2/24 = 8.3%
30                  4                    4/24 = 16.7%
40                  2                    2/24 = 8.3%
50                  3                    3/24 = 12.5%
60                  5                    5/24 = 20.8%
70                  3                    3/24 = 12.5%
80                  1                    1/24 = 4.2%
90                  2                    2/24 = 8.3%
total :           24
7 0
3 years ago
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