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sveta [45]
3 years ago
13

Give an algebraic representation of these datax|y1|14|77|1310|19​

Mathematics
1 answer:
Zolol [24]3 years ago
6 0

Answer:

y = 2x - 1

Step-by-step explanation:

Slope

for every increase of 3 in x

there's an increase of 6 in y

m = rise/run

m = 6/3

m = 2

----------------------------

Slope intercept form is

y = mx + b

To find "b" plug in m = 2 and any of the given points

using (1, 1)

1 = 2(1) + b

1 = 2 + b

b = -1

The equation is

y = 2x - 1

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Solve for y<br> (y-k)h=c
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Answer:

y=(x+kh)1/h

Step-by-step explanation:

(y-k)h=c

hy-kh=c

hy=x+kh

y=(x+kh)1/h

4 0
3 years ago
In the diagram below, ST is parallel to PQ. If ST is 4 more than PS,SR = 12, and PQ = 15, find the length of PS. Figures are not
Tpy6a [65]

Since segments ST and PQ are parallel, triangles SRT and PRQ are similar due to the AAA postulate. In general, the ratio between the corresponding sides of two similar triangles is constant; therefore,

\frac{SR}{PR}=\frac{RT}{RQ}=\frac{TS}{QP}

Furthermore,

PS=PR-RS

Finding PR and RS,

\begin{gathered} ST=4+PS \\ SR=12 \\ PQ=15 \end{gathered}

Then,

\frac{12}{PR}=\frac{TS}{15}\begin{gathered} \Rightarrow\frac{12}{PR}=\frac{4+PS}{15} \\ \Rightarrow\frac{12}{PS+12}=\frac{4+PS}{15} \end{gathered}

Solving for PS,

\begin{gathered} 12\cdot15=(PS+12)(PS+4) \\ \Rightarrow180=PS^2+16PS+48 \end{gathered}

Solve the quadratic equation in terms of PS, as shown below

\begin{gathered} \Rightarrow PS^2+16PS-132=0 \\ \Rightarrow PS=\frac{-16\pm\sqrt[]{16^2-4(-132)}}{2}=\frac{-16\pm28}{2} \\ \Rightarrow PS=-22,6 \end{gathered}

And PS is a segment; therefore, it has to be positive.

Hence, the answer is PS=6

3 0
1 year ago
Explain how to use the unit rate to make a table​
xxTIMURxx [149]

Answer:

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Example-

2:4

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6:12

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3 years ago
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1) Point A will be at (-4,4)
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3 years ago
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Please help me with this question
MA_775_DIABLO [31]

Answer:

B. 36

Step-by-step explanation:

4 0
3 years ago
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