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bonufazy [111]
3 years ago
5

-3x + 4y – 5xy ; x= -3, y = 2 Need help ASAP plz

Mathematics
2 answers:
marysya [2.9K]3 years ago
4 0

Answer:

47

Step-by-step explanation:

First, plug in the numbers.

x = -3 and y = 2.

-3(-3) + 4(2) - 5(-3)(2)

Simplify by multiplying.

-3 * -3 = 9

4 * 2 = 8

-5 * -3 * 2 = 30

Your new equation is:

9 + 8 + 30 = ?

Simplify by adding. 9 + 8 + 30 = 47

stepan [7]3 years ago
3 0

Answer:

47

Step-by-step explanation:

-3(-3) + 4(2) - 5(-3)(2)

9 + 8 + 30 = 47

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Step-by-step explanation:

2 quarters

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Simplify the following fraction 4½-2⅝​
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4 1/2 - 2 5/8

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3 years ago
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WhiThree-fifths of the members of the Spanish club are girls. There are a total of 30 girls in the Spanish club.
vesna_86 [32]

Answer:

The total members in the Spanish Club  = 50

Step-by-step explanation:

Let the total members in the Spanish Club = x

Now, number of girls in the club = 30

Three-fifths of the members are girls.

⇒ (\frac{3}{5} )  of total members x  =  30

or, (\frac{3}{5})  \times  x =  30\\

Now, solving for x, we get:

x = 30 \times\frac{5}{3}   = 50

or, x   = 50

Hence,the total members in the Spanish Club  = 50

7 0
3 years ago
6. Steve is packing sacks for treats at a party. Every sack is exactly the same. Steve has 42 candy bars and 126 lollipops. a. W
Sergeu [11.5K]

Answer:

Greatest sack = 42

1 candy bar and 3 lollipops

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Step-by-step explanation:

Represent Candy bars with C and Lollipops with L

C = 42

L= 126

Solving (a): Greatest number of treat sacks

To solve this, we simply calculate the GCF of C and L

42 = 2^1 * 3^1 * 7^1

126 = 2^1 * 3^2 * 7^1

Hence, the GCF is

GCF = 2^1 * 3^1 * 7^1

GCF = 42

Hence, greatest number of sack is 42

Solving (b): Number of treat in each sack.

To do this, we simply divide the number of C and L by the calculated GCF

For C:

Treats = \frac{C}{GCF}

Treats = \frac{42}{42}

Treats = 1

For L:

Treats = \frac{L}{GCF}

Treats = \frac{126}{42}

Treats = 3

<em>Hence, 1 candy bar and 3 lollipops</em>

8 0
3 years ago
Which of these figures has rotational symmetry?
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