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2 years ago

Please help me asap

Mathematics

2 answers:

schepotkina [342]2 years ago

6 0

3.) A *the first one*
4.) C *the last one*

Vladimir79 [104]2 years ago

3 0

<em>Answer:</em>

<em>Answer:2i29293939939dd9d9d9d9dd9</em>

<em>Answer:2i29293939939dd9d9d9d9dd9Step-by-step explanation:</em>

<h3><em>Answer:2i29293939939dd9d9d9d9dd9Step-by-step explanation:fiffurueeheheebe</em></h3>

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One-quarter of the counters in a tub are red. The rest of the counters are green. If there are 48 green counters, how many red c

scZoUnD [109]

There are 16 red counters there.

<h3>Fractions and proportions</h3>

If one-quarter of the counters in a tub are red and the rest are green, then there are three-quarter of the counter in the tub.

Let the total counter be x such that

3/4x = 48

3x = 4 * 48

x = 4 * 16

x = 64

Determine the amount of red counter

Red counter = 64 - 48

Red counter = 16

Hence there are 16 red counters there.

Learn more on proportion here; brainly.com/question/1496357

#SPJ1

6 0

2 years ago

4. Dean Pelton wants to perform calculations to impress the accreditation consultants, but upon asking for information about GPA

Leya [2.2K]

Answer:

the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

Step-by-step explanation:

Let assume that n should represent the number of the students

SO, $\bar x$ can now be the sample mean of number of students in GPA's

To obtain n such that $P( \bar x \leq 2.3 ) \leq .04$

⇒ $P( \bar x \geq 2.3 ) \geq .96$

However ;

$E(x) = \int\limits^4_2 Dx (2+e^{-x} ) 4x = D \\ \\ = D(e^{-x} (e^xx^2 - x-1 ) ) ^D_2 = 12.314 D$

$E(x^2) = D\int\limits^4_2 (2+e^{-x})dx \\ \\ = \dfrac{D}{3}[e^{-4} (2e^x x^3 -3x^2 -6x -6)]^4__2}}= 38.21 \ D$

Similarly;

$D\int\limits^4_2(2+ e^{-x}) dx = 1$

⇒ $D*(2x-e^{-x} ) |^4_2 = 1$

⇒ $D*4.117 = 1$

⇒ $D= \dfrac{1}{4.117}$

$\mu = E(x) = 2.991013 ; \\ \\ E(x^2) = 9.28103$

∴ $Var (x) = E(x^2) - E^2(x) \\ \\ = .3348711$

Now; $P(\bar \geq 2.3) = P( \bar x - 2.991013 \geq 2.3 - 2.991013) \\ \\ = P( \omega \geq .691013) \ \ \ \ \ \ \ \ \ \ (x = E(\bar x ) - \mu)$

Using Chebysher one sided inequality ; we have:

$P(\omega \geq -.691013) \geq \dfrac{(.691013)^2}{Var ( \omega) +(.691013)^2}$

So; $(\omega = \bar x - \mu)$

⇒ $E(\omega ) = 0 \\ \\ Var (\omega ) = \dfrac{Var (x_i)}{n}$

∴ $P(\omega \geq .691013) \geq \dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2}$

To determine n; such that ;

$\dfrac{(.691013)^2}{\frac{.3348711}{n}+(691013)^2} \geq 0.96 \\ \\ \\ (.691013)^2(1-.96) \geq \dfrac{-3348711*.96}{n}$

⇒ $n \geq \dfrac{.3348711*.96}{.04*(.691013)^2}$

$n \geq 16.83125$

Thus; we can conclude that; the minimum records to be retrieved by using Chebysher - one sided inequality is 17.

5 0

2 years ago

Find the value of x.

Mamont248 [21]

Honestly no idea... sorry

5 0

3 years ago

Select the correct answer. Jason inherited a piece of land from his great-uncle. Owners in the area claim that there is a 45% ch

GREYUIT [131]

Answer:

Option A 0.1698

Step-by-step explanation:

Given that Jason has a chance for getting oil as 45%

THe kit he buys show accurate result with 80% probability

Let A1- Event that the land has oil

A2 - Event that the land has no oil

B- The test gives negative result

A1 and A2 are mutually exclusive and exhaustive

P(A1) = 0.45 and P(A2) =0.55

Hence we can use Baye theorem

Then P(B) = P(A1B)+P(A2B)= $0.45(0.20)+0.55(0,80)\\=0.09+0.0.44\\=0.53$

Reqd prob =P(A1/B) =

$\frac{P(A1B)}{P(B)}\\ =\frac{0.09}{0.53}\\\\=0.1698$

3 0

3 years ago

Kandice notices that 2/7 of a gallon of milk is on the top shelf of the refrigerator, and 3/5 of gallon of milk is on the bottom

Brilliant_brown [7]

The answer is 24/35. i would tell you to simplify but it is already in its simpliest form.

8 0

3 years ago

Read 2 more answers

Please help me asap​

Please help me asap