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2 years ago

How does 0.008 compare to 0.08

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

5 0

I can give you 2 examples of how does 0.008 compare to 0.08

1st example..

0.008 is 8 thousandths but 0.08 is 8 hundredths (8,000) and (800)

2nd example...

0.008 is greater than 0.08

hoped this helped!

il63 [147K]2 years ago

4 0

0.008 compares to 0.08 because 8 in 0.008 is in the one thousands place and 8 in 0.08 is in the one hundreds plase

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Answer:

3. f(x + 3)

Step-by-step explanation:

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The graph, if translated 3 units to the left will include the point A.

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2 years ago

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Step-by-step explanation:

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2 years ago

Find derivative problem<br> Find B’(6)

dalvyx [7]

Answer:

$B^\prime(6) \approx -28.17$

Step-by-step explanation:

We have:

$\displaystyle B(t)=24.6\sin(\frac{\pi t}{10})(8-t)$

And we want to find B’(6).

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$\displaystyle B^\prime(t)=\frac{d}{dt}[24.6\sin(\frac{\pi t}{10})(8-t)]$

We can move the constant outside:

$\displaystyle B^\prime(t)=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)]$

Now, we will utilize the product rule. The product rule is:

$(uv)^\prime=u^\prime v+u v^\prime$

We will let:

$\displaystyle u=\sin(\frac{\pi t}{10})\text{ and } \\ \\ v=8-t$

Then:

$\displaystyle u^\prime=\frac{\pi}{10}\cos(\frac{\pi t}{10})\text{ and } \\ \\ v^\prime= -1$

(The derivative of u was determined using the chain rule.)

Then it follows that:

$\displaystyle \begin{aligned} B^\prime(t)&=24.6\frac{d}{dt}[\sin(\frac{\pi t}{10})(8-t)] \\ \\ &=24.6[(\frac{\pi}{10}\cos(\frac{\pi t}{10}))(8-t) - \sin(\frac{\pi t}{10})] \end{aligned}$

Therefore:

$\displaystyle B^\prime(6) =24.6[(\frac{\pi}{10}\cos(\frac{\pi (6)}{10}))(8-(6))- \sin(\frac{\pi (6)}{10})]$

By simplification:

$\displaystyle B^\prime(6)=24.6 [\frac{\pi}{10}\cos(\frac{3\pi}{5})(2)-\sin(\frac{3\pi}{5})] \approx -28.17$

So, the slope of the tangent line to the point (6, B(6)) is -28.17.

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2 years ago

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Lady bird [3.3K]

Answer:

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Step-by-step explanation:

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