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djverab [1.8K]
3 years ago
5

CAN SOMEONE HELP MEEEE OUTTT!!!

Mathematics
1 answer:
poizon [28]3 years ago
4 0

Step-by-step explanation:

the answer is sqrt(7)

using pythagoras theorem

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15
Butoxors [25]

Step-by-step explanation:

1/2 represents every fraction, where the denominator (bottom part) is twice the numerator (top part).

like 4/8 or 6/12 or 128/256 or ...

what do we need in the denominator to calculate with 15/16 ?

the same : 16.

and what is half of 16 ? 8.

so, we need the 1/2 based on 16th = 8/16.

so, the dog ate 8/16 (1/2) of the original 15/16.

what was left was

15/16 - 8/16 = 7/16 pound

7 0
2 years ago
If you wish to warm 40 kg of water by 18 ∘C for your bath, find what the quantity of heat is needed. Express your answer in calo
Harman [31]

Answer:

Quantity of heat needed (Q) = 722.753 × 10³

Step-by-step explanation:

According to question,

Mass of water (m) = 40 kg

Change in temperature ( ΔT) = 18°c

specific heat capacity of water = 4200 j kg^-1 k^-1

The specific heat capacity is the amount of heat required to change the temperature of 1 kg of substance to 1 degree celcius or 1 kelvin .

So, Heat (Q) = m×s×ΔT

Or,          Q = 40 kg × 4200 × 18

or,           Q = 3024 × 10³ joule

Hence, Quantity of heat needed (Q) = 3024 × 10³ joule    

In calories 4.184 joule = 1 calorie

So, 3024 × 10³ joule = 722.753 × 10³

6 0
3 years ago
Solve the inequality and describe the solution set.
Ghella [55]
I think the answer is 6 because if you think about its y - 6 but its under less of 12 so it has to be 6

8 0
4 years ago
The ratio of boys to girls in a class is 3:2. If there are 36 boys then how many girls are in the class
Mama L [17]

Answer:

They are 12 girls in class

Step-by-step explanation:

7 0
3 years ago
I️ have travelled around 75% of the edge of a circular path for 10 miles. What is the diameter of the circular path
KonstantinChe [14]
The circumference of a circle is equal to pi * diameter

So 10 miles = 0.75 * pi * d

10/(0.75*pi) = d

d = <span>4.244 miles</span>
5 0
3 years ago
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