1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nookie1986 [14]
2 years ago
9

11/3 divided by what equals 11​

Mathematics
1 answer:
BARSIC [14]2 years ago
4 0

Answer:

Divide by 1/3

Step-by-step explanation:

Let x be the unknown number

11/3 ÷x =11

Multiply each side by x

11/3 ÷x  *x=11*x

11/3 = 11x

Divide each side by 11

11/3 ÷11 = 11x/11

11/3 ÷11 = x

Copy dot flip

11/3 * 1/11 =x

1/3 =x

You might be interested in
Find the sum of the positive integers less than 200 which are not multiples of 4 and 7​
taurus [48]

Answer:

12942 is the sum of positive integers between 1 (inclusive) and 199 (inclusive) that are not multiples of 4 and not multiples 7.

Step-by-step explanation:

For an arithmetic series with:

  • a_1 as the first term,
  • a_n as the last term, and
  • d as the common difference,

there would be \displaystyle \left(\frac{a_n - a_1}{d} + 1\right) terms, where as the sum would be \displaystyle \frac{1}{2}\, \displaystyle \underbrace{\left(\frac{a_n - a_1}{d} + 1\right)}_\text{number of terms}\, (a_1 + a_n).

Positive integers between 1 (inclusive) and 199 (inclusive) include:

1,\, 2,\, \dots,\, 199.

The common difference of this arithmetic series is 1. There would be (199 - 1) + 1 = 199 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times ((199 - 1) + 1) \times (1 + 199) = 19900 \end{aligned}.

Similarly, positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 4 include:

4,\, 8,\, \dots,\, 196.

The common difference of this arithmetic series is 4. There would be (196 - 4) / 4 + 1 = 49 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 49 \times (4 + 196) = 4900 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 7 include:

7,\, 14,\, \dots,\, 196.

The common difference of this arithmetic series is 7. There would be (196 - 7) / 7 + 1 = 28 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 28 \times (7 + 196) = 2842 \end{aligned}

Positive integers between 1 (inclusive) and 199 (inclusive) that are multiples of 28 (integers that are both multiples of 4 and multiples of 7) include:

28,\, 56,\, \dots,\, 196.

The common difference of this arithmetic series is 28. There would be (196 - 28) / 28 + 1 = 7 terms. The sum of these integers would thus be:

\begin{aligned}\frac{1}{2}\times 7 \times (28 + 196) = 784 \end{aligned}.

The requested sum will be equal to:

  • the sum of all integers from 1 to 199,
  • minus the sum of all integer multiples of 4 between 1\! and 199\!, and the sum integer multiples of 7 between 1 and 199,
  • plus the sum of all integer multiples of 28 between 1 and 199- these numbers were subtracted twice in the previous step and should be added back to the sum once.

That is:

19900 - 4900 - 2842 + 784 = 12942.

8 0
3 years ago
If Alicia can read 3 pages in 1 minute, how long would it take her to read 33 pages?
Bond [772]

divide total pages by pages per minute

33 / 3 = 11 minutes

7 0
3 years ago
(8x- 1) (11X - 25) (15y - 48) ​
alexgriva [62]

1320xyX−4224xX−165yX−3000xy+528X+9600x+375y−12001320xyX-4224xX-165yX-3000xy+528X+9600x+375y-1200

5 0
3 years ago
What is the interquartile range (IQR) of the following data set 17 16 21 15 25 22 18 23 17
Pepsi [2]

IQR = 6

First locate the median Q_{2} at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles Q_{1} and Q_{3} located at the centre of the data to the left and right of the median.

Note that if any of the above are not whole values then they are the average of the values either side of the centre.

rearrange data in ascending order

15 16 ↓17 17 18 21 22 ↓23 25

                     ↑

Q_{2} = 18

Q_{1} = \frac{16+17}{2} = 16.5

Q_{3} = \frac{22+23}{2} = 22.5

IQR = Q_{3} - Q_{1} = 22.5 - 16.5 = 6




4 0
2 years ago
a previous analysis of paper boxes showed that the standard deviation of their lengths is 15 millimeters. A packers wishes to fi
vladimir1956 [14]

Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

= 864.36 boxes

Based on the options above, we can round it up to 97 boxes.

8 0
2 years ago
Other questions:
  • Solve the separable initial value problem. 1. y' = ln(x)(1 + y2), y(1) = 3 = y= tan(xlnx-x+1+arctan(3) 2. y' = 9x? V1 + x? (1 +
    5·1 answer
  • Mercury poisoning is dangerous overload of mercury within the body. A major source of mercury within the body, A major source of
    15·1 answer
  • The surface area of a cone with radius r units and slant height s units is shown below: Surface area = 3.14(rs + r2) Part A: If
    8·1 answer
  • Put it in an Equation and find the solution
    12·2 answers
  • Find the equation of the line that passes through the points (6,14) and is parallel to y=-4/3x-1
    14·1 answer
  • Which set of line segments can be used to construct a triangle?
    5·1 answer
  • Ava and josh need 2/3 cups of sugar to bake their cookies. Their measuring cup is divided into sixths. What fraction of the meas
    5·1 answer
  • 10 POINTS I WILL GIVE BRAINLIEST
    7·1 answer
  • Points A(8,4)&B(-2,4) lie on a line .AB is parallel to which axis
    10·1 answer
  • If a line passes through the points (-2, 9) and (1, 3). what would be the slope, Y-intercept, and the slope-intercept form?
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!