The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
To learn more on quadratic functions: brainly.com/question/5975436
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There would be 8 ones, 4 fives, 12 tens, and 4 twenties. That together would be about $228
Answer:
Length: 84 ft
Width: 56 ft
Step-by-step explanation:
Let's define some variables first.
Call the length l and width w.
We know that w = 2/3l. Therefore, we can express w in terms of l with this expression.
Now, let's set up an equation. The flower garden is rectangular, and 280 feet of fencing are used to enclose the garden. This represents perimeter.
Remember the formula for perimeter of a rectangle: 2l + 2w
Let's substitute 2/3l for w:
2l + 2*2/3l = P
2l + 4/3l = 280
2 4/3l = 280
10/3l = 280
l = 84
Now, we know that the length is equal to 84 feet. We can multiply 84 feet by 2/3 to find the width.
84*2/3 = 56
Length: 84 ft
Width: 56 ft
Let's plug these values into the formula and see if they give us the correct perimeter:
2l + 2w = P
2*84 + 2*56 = P
168 + 112
= 280 feet
These are the correct dimensions!
Hope this helps! You can reach out to me if you have further questions or concerns! :)
Answer:
Step-by-step explanation:
Tough call.
You may have to use Newton's Method or something like that.
Graph y=2^x and then graph n/x on the same set of axes. You may have to assign some arbitrary value to n to make this work. From the graph you can read off the approximate coordinates of the point of intersection.
