divide total pages by pages per minute
33 / 3 = 11 minutes
1320xyX−4224xX−165yX−3000xy+528X+9600x+375y−12001320xyX-4224xX-165yX-3000xy+528X+9600x+375y-1200
IQR = 6
First locate the median
at the centre of the data arranged in ascending order. Then locate the lower and upper quartiles
and
located at the centre of the data to the left and right of the median.
Note that if any of the above are not whole values then they are the average of the values either side of the centre.
rearrange data in ascending order
15 16 ↓17 17 18 21 22 ↓23 25
↑
= 18
=
= 16.5
=
= 22.5
IQR =
-
= 22.5 - 16.5 = 6
Answer:
864.36 boxes
Step-by-step explanation:
In the question above, we are given the following values,
Confidence interval 95%
Since we know the confidence interval, we can find the score.
Z score = 1.96
σ , Standards deviation = 15mm
Margin of error = 1 mm
The formula to use to solve the above question is given as:
No of boxes =[ (z score × standard deviation)/ margin of error]²
No of boxes = [(1.96 × 15)/1]²
= 864.36 boxes
Based on the options above, we can round it up to 97 boxes.