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3 years ago

Please help me guys please please please

Physics

1 answer:

givi [52]3 years ago

4 0

Answer:

Mass = 2154 grams

Explanation:

Given the following data;

Acceleration = 520m/s²

Force = 11.2N

To find the mass;

Force = mass * acceleration

Mass = force/acceleration

Substituting into the equation, we have;

Mass = 11.2/520

Mass = 2.154 kg

Therefore, the value of mass in grams;

1000 grams = 1 kilograms

x grams = 2.154 kilograms

Cross-multiplying, we have;

2.154 * 1000 = 2154 grams.

Mass = 2154 grams.

Therefore, the mass of the model rocket is equal to 2154 grams.

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A busy chipmunk runs back and forth along a straight line of acorns that has been set out between its burrow and a nearby tree.

dmitriy555 [2]

<u>Answer:</u>

Chipmunk's average acceleration during the 2.07 s time interval = 0.1256 $m/s^2$

<u>Explanation:</u>

We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

In this case we need to find acceleration value, we have initial velocity = 1.47 m/s, final velocity = 1.73 m/s and time taken = 2.07 seconds.

Substituting

1.73 = 1.47 + a * 2.07

a = 0.1256 $m/s^2$

Chipmunk's average acceleration during the 2.07 s time interval = 0.1256 $m/s^2$

7 0

4 years ago

What is the new pressure of 150 ml of a gas that is compressed to 50 ml when the original pressure was 3.0 atm and the temperatu

Firlakuza [10]

Answer: 9.0 atm

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=3.0atm\\V_1=150mL\\P_2=?mmHg\\V_2=50mL$

Putting values in above equation, we get:

$3.0\times 150mL=P_2\times 50mL\\\\P_2=9.0atm$

Thus new pressure of 150 ml of a gas that is compressed to 50 ml is 9.0 atm

5 0

4 years ago

hockey puck slides across the ice with an initial velocity of 7.2 m/s. It has a deceleration of 1.1 m/s2 and is traveling toward

dimulka [17.4K]

For this use the formula:

d = Vo * t - (at^2) / 2

Clearing t:

t = d/(v + 0.5*a)

Replacing:

t = 5 m / (7.2 m/s + 0.5 * (-1.1 m/s²)

Resolving:

t = 5 m / (7.2 m/s + (-0.55 m/s²)

t = 5 m / 6.65 m/s

t = 0.75 s

Result:

The time will be <u>0.75 seconds.</u>

7 0

3 years ago

Read 2 more answers

The cannon on a battleship can fire a shell a maximum distance of 36.0 km.

Paraphin [41]

(a)The initial velocity of the shell will be 594.27 m/sec

(b)The maximum height it reaches will be 9000 m.

c)101.249 m meters lower will its surface be 36.0 km from the ship along a horizontal line parallel to the surface of the ship.

d)The error could be significant compared to the size of a target. Option C is correct.

<h3>What is velocity?</h3>

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

m is the mass of the block = Kg.

u is the initial velocity of fall = m/sec

h is the distance of fall = m

g is the acceleration of free fall = m/sec²

v is the hitting velocity of =?

The range of the projectile is;

$\rm R = \frac{u^2 sin 2 \theta }{g} \\\\ 36 \times 10^ 3 = \frac{U^2 sin 45^0}{9.81} \\\\ U= 594.27 \ m/sec$

The maximum height of the projectile is;

$\rm H = \frac{u^2 sin 2 \theta }{2g} \\\\ H = \frac{(594.27)^2\times (sin 45)^2}{2 \times 9.81 } \\\\ H = 9000 \ m$

The distance between its surface and the ship, measured in a horizontal arc parallel to the surface, will be 36.0 kilometers. The distance from the lower surface is found as;

$\rm( R_e + h)^2 = R_e^2+(36)^2 \\\\ (R_e)^2 = h^2+2R_e h= R_e^2 + 12196 \\\\ h^2 + 12800 h - 1296 = 0 \\\\ h = 101.249 \ m$

An error is a mistaken or erroneous action. In some contexts, an error is interchangeable with a mistake.

The difference between the calculated value and the original value is known as the error. The inaccuracy may be large in comparison to the target's size. Option C is correct.

Hence the initial velocity of the shell, maximum height, and the distance from the lower surface will be 594.27 m/sec,9000 m, and 101.249 m and option c for question d are correct respectively.

To learn more about the velocity, refer to the link: brainly.com/question/862972.

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4 0

2 years ago

In the first video for chapter 29, we looked at the emission spectrum of excited gases. In this video, we look at the __________

Elan Coil [88]

Although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.

<h3>What is the transmission spectrum?</h3>

The transmission spectrum indicates the light portion having a given wavelength that can be passed through a filter.

This spectrum (transmission spectrum) depends on the physical separation of the particles that form the filter.

In conclusion, although the video is not found here, the sentence makes reference to the transmission spectrum of colored filters.

Learn more about the transmission spectrum here:

brainly.com/question/1287536

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6 0

3 years ago

Please help me guys please please please​

Please help me guys please please please