Yes that looks correct to me. good luck!!
Answer:
The astronaut can throw the hammer in a direction away from the space station. While he is holding the hammer, the total momentum of the astronaut and hammer is 0 kg • m/s. According to the law of conservation of momentum, the total momentum after he throws the hammer must still be 0 kg • m/s. In order for momentum to be conserved, the astronaut will have to move in the opposite direction of the hammer, which will be toward the space station.
Explanation:
To solve this problem it is necessary to apply the concepts related to the magnetic field.
According to the information, the magnetic field INSIDE the plates is,

Where,
Permeability constant
Electromotive force
r = Radius
From this deduction we can verify that the distance is proportional to the field

Then the distance relationship would be given by




On the outside, however, it is defined by

Here the magnetic field is inversely proportional to the distance, that is

Then,




-- If acceleration and velocity are in the same direction,
then the object is speeding up.
-- If acceleration and velocity are in opposite directions,
then the object is slowing down.
-- If acceleration is perpendicular to velocity, then the object
is moving on a circular curve at constant speed.