Length of object . how much distance increase or decrease force
Answer:
25.8 minutes
Explanation:
The time it takes for the journey if the current velocity is maintained:
T=144/48= 3 hours.
The time it takes for the journey if he increases his velocity to 56 km/hour:
144-56 = approx. 2.57 hours.
Time saved =.43*60=25.8 minutes
The maximum value of θ of such the ropes (with a maximum tension of 5,479 N) will be able to support the beam without snapping is:

We can apply the first Newton's law in x and y-direction.
If we do a free body diagram of the system we will have:
x-direction
All the forces acting in this direction are:
(1)
Where:
- T(1) is the tension due to the rope 1
- T(2) is the tension due to the rope 2
Here we just conclude that T(1) = T(2)
y-direction
The forces in this direction are:
(2)
Here W is the weight of the steel beam.
We equal it to zero because we need to find the maximum angle at which the ropes will be able to support the beam without snapping.
Knowing that T(1) = T(2) and W = mg, we have:



T(1) must be equal to 5479 N, so we have:


Therefore, the maximum angle allowed is θ = 37.01°.
You can learn more about tension here:
brainly.com/question/12797227
I hope it helps you!
Answer:
A) The distance traveled by the ball in the Up-down dimension is 30 m
The displacement of the ball in the up-down direction is 0 m
B) The distance the ball travels in the east west direction is 45 m [East]
The displacement of the ball is the east-west direction is 45 m [East]
Explanation:
The long measures of the ball motion are;
The maximum height reached = 15 m Up
The horizontal distance traveled by the ball during flight = 30 m East
The distance the receiver ran with the ball after the ball was caught = 15 m East
A) The distance traveled by the ball in the Up-down dimension = 15 m up + 15 m backdown = 30 m in the up-down direction
The displacement of the ball in the up-down direction, d = 15 m + (-15 m) = 0 m
B) The distance the ball travels in the east west direction = 30 m [E] + 15 m [E] = 45 [E]
The displacement of the ball is the east-west direction, d = 30 m + 15 m = 45 m [E].