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Dennis_Churaev [7]
3 years ago
13

What is the molar mass of 1-butene if 5.38 × 1016 molecules of 1-butene weigh 5.00 μg?

Chemistry
1 answer:
xenn [34]3 years ago
4 0
<h3>Answer:</h3>

             Molar Mass =  56 g.mol⁻¹

<h3>Explanation:</h3>

Data Given:

                   Mass  =  5.00 μg  =  5.0 × 10⁻⁶ g

                   Number of Molecules  =  5.38 × 10¹⁶ Molecules

Step 1: Calculate Moles of 1-Butene:

                      As we know one mole of any substance contains 6.022 × 10²³ particles (atoms, ions, molecules or formula units). This number is also called as Avogadro's Number.

The relation between Moles, Number of Particles and Avogadro's Number is given as,

                          Number of Moles  =  Number of Particles ÷ 6.022 × 10²³

Putting values,

                          Number of Moles  =  5.38 × 10¹⁶ Molecules ÷ 6.022 × 10²³

                          Number of Moles  =  8.93 × 10⁻⁸ Moles

Step 2: Calculate Molar Mass of 1-Butene:

As,

                          Mole  =  Mass ÷ M.Mass

Solving for M.Mass,

                          M.Mass  =  Mass ÷ Mole

Putting values,

                          M.Mass  =  5.0 × 10⁻⁶ g ÷ 8.93 × 10⁻⁸ mol

                          M.Mass =  55.99 g.mol⁻¹ ≈ 56 g.mol⁻¹

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what is the boiling point of the solution resulted from the dissolving of 32.5g of NaCl in 250.0g of water?
suter [353]

Answer:

The boiling point of this solution is 102.28 °C

Explanation:

<u>Step 1:</u> Data given

Mass of Nacl = 32.5 grams

Molar mass of NaCl = 58.45 g/mol

Mass of Water = 250 grams

Boiling point of water = 100°C

<u>Step 2: </u>Calculate number of moles

Number of moles = mass of NaCl / Molar mass of NaCl

Number of moles = 32.5 grams /58.45 g/mol = 0.556 moles

<u>Step 3:</u> Calculate molality

Molality = Number of moles / mass of water

Molality = 0.556 moles / 0.250 kg of water

Molality = 2.224 molal

NaCl releases twice as many moles of ions, the total molality of this solution is also twice: 4.448 molal

Step 4: Calculate boiling point

dT =( 0.512 C / molal)*4.448 molal)

dT = 2.28

The boiling point of this solution is 100 °C + 2.28 °C = 102.28 °C

8 0
3 years ago
Si dos elementos tienen igual valor del número cuántico n y diferente l, ml y ms entonces deben estar en : El mismo orbital, per
OlgaM077 [116]

Answer:

El mismo nivel, pero diferente subnivel y orbital

Explanation:

En un átomo, el número cuántico principal n muestra el nivel de energía del electrón.

Si dos electrones tienen el mismo valor del número cuántico principal n, simplemente significa que están en el mismo nivel de energía.

Sin embargo, cuando los números cuánticos l y ml difieren, los electrones deben estar en diferentes subniveles y orbitales.

8 0
3 years ago
A compound contains 78.14% B and 21.86% H by mass and has a molar mass of 27.67 g/mol. What is the molecular formula of the comp
ziro4ka [17]

Answer:

The molecular formula of the compound is B₂H₆

Explanation:

From the question given above, the following data were obtained:

Composition of Boron (B) = 78.14%

Composition of Hydrogen (H) = 21.86%

Molar mass of compound = 27.67 g/mol

Molecular formula =?

Next, we shall determine the empirical formula of the compound. This can be obtained as follow:

B = 78.14%

H = 21.86%

Divide by their molar mass

B = 78.14 / 11 = 7.104

H = 21.86 / 1 = 21.86

Divide by the smallest

B = 7.104 / 7.104 = 1

H = 21.86 / 7.104 = 3

Thus, the empirical formula of the compound is BH₃

Finally, we shall determine the molecular formula of the compound. This can be obtained as illustrated below:

Molecular formula = empirical formula × n

Molecular formula = [BH₃]ₙ

Thus, we shall determine the value of n to obtain the molecular formula. The value of n can be obtained as follow:

[BH₃]ₙ = 27.67

[11 + (3×1)]n = 27.67

[11 + 3]n = 27.67

14n = 27.67

Divide both side by 14

n = 27.67 / 14

n = 2

Molecular formula = [BH₃]ₙ

Molecular formula = [BH₃]₂

Molecular formula = B₂H₆

4 0
3 years ago
What is the final, balanced equation that is formed by combining these two half reactions?
OLga [1]

Answer:

Cu + 2NO3- + 4H+ ---------> Cu2+ + 2NO2 + 2H20

Explanation:

The half reactions are;Cu ----------> Cu2+ + 2e-

NO3 + 2e + 2H* —------> N02 + H20

It is worthy to note that oxidation is the an increase in oxidation number while reduction is a decrease in oxidation number.

In the first half reaction involving Copper, copper has been oxidized as its oxidation number increased from 0 to +2.

IN the reduction half reaction, NO3- has been reduced as its oxidation number decreased from +5 to +4.

In balancing half reactions, the following must be observed;

1. split the reactions into half equations, one for oxidation and the other for reduction.

Cu ------> Cu2+ + 2e-   ( oxidation)

NO3- + 2e- -----> NO2   (reduction).

2. balance on half with respect to atoms and charges.

3. balance the other half with respect to atoms and charges

4. balance by adding H+ ions in acidic solution

NO3- + e- -------> NO2

(-1 )       (-1)             (0)

NO3- + 2H+ +e- -------> NO2

(-1)       (+2)     (-1)            (0)

5. balance hydrogen by adding water molecules

NO3 - + 2H+ + e - -------->  NO2 + H2O

6. combine both equations

Cu ---> Cu2+ + 2e-                                  *1

NO3- + 2H+ + e- -------> NO2 + H2O      *2

= Cu -----> Cu2+ + 2e-

2NO3- +4H+ + 2e- -------> 2 NO2 + 2H20

Combined equation  = Cu + 2NO3- + 4H+ ---------> Cu2+ + 2NO2 + 2H20

4 0
3 years ago
From the following isotope notation, detemine the number of protons, neutrons &amp; electrons
Crazy boy [7]

Answer:

so the correct answer would be the 3rd one.

26 proton, 32 neutrons, 26 electrons.

Explanation:

Protons and electrons are the same, which is also the same as the atomic number. in that case that would be 26.

Therefore, proton=electron =26

for neutron, you just have to subtract the mass number to the electron/proton.

n = m - e

n= 58-26

neutron =32.

Hope that helps.

3 0
3 years ago
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