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kvv77 [185]
3 years ago
8

Please help Edgen. chemistry Lab: Reaction Rate Assignment: Lab Report

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
5 0

Answer:

here its probably late but this is my whole lab report. also please give brainliest. this took a while.

Explanation:

edge

Download pdf
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A 15.33 g sample of magnesium oxide is found to contain 12.67 g of magnesium. What is the percent (by mass) composition of
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Answer:

Explanation:

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Why doesn't it matter which nonradioactive isotope of oxygen you breathe?
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Isotopes of an element have same atomic number (number of protons) but vary in the mass number (number of neutrons). The chemical reactivity of an element is not affected by the change in mass number. So, for stable isotopes of Oxygen, (Oxygen-16, Oxygen-17 and Oxygen-18) the biochemical pathway of oxygen breathed in during respiration remains unaffected even with different isotopes. Only the radioactive isotopes of oxygen when breathed in may cause serious health hazards as they emit radiations that may damage the internal organs in the body.

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4 years ago
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What is the IUPAC name of the following compound? There is a structure for an organic molecule. It has 6 carbons in its chain, a
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Answer:

The answer to your question is below

Explanation:

Process

1.- Look for the longest chain

2.- Number the carbons of the main chain starting from the corner where the double bond is closer.

3.- Circle the branches

4.- Start naming the number where the branch is and the name of the branch.

5.- Name the main branch with the ending -ene.

                    5-methyl, 1-hexene or 5-methyl, hex-1-ene

See gthe structure below.

4 0
3 years ago
One sphere has a radions of 181 cm, another has a radius of 5.01 cm. What is the difference in volume (in cubic centimeters) bet
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Answer:

2.4*10^{7}cm^{3}

Explanation:

First you should calculate the volume of a big sphere,so:

V_{big}=\frac{4}{3}\pi r^{3}

V_{big}=\frac{4}{3}\pi (181cm)^{3}

V_{big}=2.4*10^{7}cm^{3}

Then you calculate the volume of a small spehre, so:

V_{small}=\frac{4}{3}\pi r^{3}

V_{small}=\frac{4}{3}\pi (5.01cm)^{3}

V_{small}=5.3*10^{2}cm^{3}

Finally you subtract the two quantities:

V_{big}-V_{small}=2.4*10^{7}cm^{3}-5.3*10^{2}cm^{3}

V_{big}-V_{small}=2.4*10^{7}cm^{3}

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3 years ago
Name the following bases<br> -Ba(OH)2<br> - Ca(OH)2<br> -RbOH
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Ba(OH)_2\rightarrow \bold{\green{Barium\: hydroxide}}

Ca(OH)_2\rightarrow \bold{\red{Calcium\: hydroxide}}

RbOH \rightarrow \bold{\blue{Rubidium \:hydroxide}}

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