Answer:NADH donates it electron to complex I a higher energy level than other complexes while FADH donates it electron to complex II a lower energy complex.
Explanation:
Both NADH and FADH are shuttle of high energy electrons originally extracted from food into the inner mitochondrial membrane.
NADH donate it electron to a flavoprotein consisting of FMN prosthetic group and an iron-sulphur protein in ETC complex-I. Two electrons and one hydrogen ion are are transferred from NADH to the flavin prosthetic group of the enzyme.
While the electrons from FADH2 enters the ETC (electron transport chain) at the level of co-enzyme Q (complex II). This step does not librate enough energy to act as a proton pump.
So NADH produces 2.5 ATP during the ETC and oxidative phosphorylation because it donates its electron to Complex I, which pump more electrons across the membrane than other complexes.
The correct answer is Karl will get sick and Jose will not this time, but neither will get this influenza again since they both will have acquired active immunity to it.
In the case of Jose artificially active immunity has been induced due to vaccination. A vaccine instigates a primary response against the antigen without resulting in any signs of the disease. On the other hand, Karl will acquire active immunity naturally in future, as when an individual get exposed to a live pathogen, he or she develops the disease, and turns immune as an outcome of the primary immune response.
Answer:
The recombination frequency between two genes exhibits a positive correlation with the distance between them, that is, farther they are, and more will be the chance of recombination. Thus, recombination frequency is used to signify distance among the two genes, for example, 1 percent recombination frequency demonstrates distance of 1 map unit.
Let us consider that the heterozygous female of genotype AaBb can generate four kinds of gametes, that is, AB, Ab, aB and ab. Of these, the two gametes are the outcomes of recombination, or it can be said that 50 percent are recombinants. Thus, it can be concluded that in case of two linked genes, the maximum probable recombination frequency is 50 percent.
This shows that any genes, which are distant than 50 map units will function as unlinked and will function as if they were on distinct chromosomes, and the frequency of recombinant frequency will be 50 percent.
In the given question, it is given that the map distance between the two genes is 80 map units, that is, more than 50 map units. The maximum probable recombinant offspring will be 50 percent of the entire offspring.
All of them. Forests are considered natrual enviornment and people/buildings are man-made environment
sorry for bad spelling
They are formed primarily on the cell's Ribosomes.
