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sattari [20]
3 years ago
11

Arc Length and Radians question- please help! Will mark brainliest! Is 20pts!

Mathematics
1 answer:
scoray [572]3 years ago
4 0

Answer:

69°

Step-by-step explanation:

Theta/360 × 2 × pi × r = arc length

Theta/360 × 2 × 3.14 × 10 = 12

Theta = 68.7898089

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melisa1 [442]

Answer:

(x-2)^2-11

Step-by-step explanation:

3 0
3 years ago
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What is the measure of o
Helga [31]

Answer:

D

Step-by-step explanation:

We need the formula for arc length (in radians) to solve this problem. The formula is:

s=r \theta

Where

s is the arc length

r is the radius of the circle

\theta is the intercepted angle

In this diagram, we can see that  \theta  is beign intercepted by the big arc with measure 20 cm. So arc length, s, is 20

Also, if we look, we see that the radius is 5 cm, so r = 5

Now, we substitute into formula and find \theta:

s=r\theta\\20=5\theta\\\theta=\frac{20}{5}\\\theta=4

This is given in radians, so \theta is 4 radians

D is the correct answer choice.

6 0
3 years ago
15 = x + 4<br> whats the answer
stealth61 [152]

Answer:

11

Step-by-step explanation:

15-4 = x

15-4 = 11

x = 11

to isolate x, you move 4 to the other side and it becomes 15-4 = x

4 0
3 years ago
10m^2 of tiles cover a pool, the pool is shaped as a square, so all four edges are the same, and the depth is constant but not e
nignag [31]
Assume:

Size of sides = x m
Depth of the pool = y m

Therefore, surface area = x^2+4xy =10 m^2

Then, y = (10-x^2)/(4x)

Now,
Volume (V) = x^2*y = x^2*y =x^2(10-x^2)/4x = (10x-x^3)/4 = 1/4(10x-x^3)
For maximum volume, first derivative of volume function is equal to zero.
That is,
dV/dx =0 = 1/4(10-3x^2)
Then,
1/4(10-3x^2) = 0
10-3x^2 = 0
3x^2=10
x= sqrt (10/3) = 1.826 m
And
y= (10-1.826^2)/(4*1.826) = 0.913 m

Therefore,
V= 1.826^2*0.913 = 3.044 m^3
3 0
3 years ago
Which is the answer. A B C D?
MakcuM [25]

Answer:

I’m pretty sure it’s B

Step-by-step explanation:

4 0
3 years ago
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