I’m not sure which of these you meant to type so I answered both ways
B=(RT-4)/6 multiply by 6
6B= RT-4. Add 4
6B+4= RT. Divide by R
(6B+4)/R = T
Or B=RT -4/6. Multiply by 6
6B=6RT -4. Add 4
6B+4= 6RT. Divide by 6R
(6B-4)/6R = T. Reduce
(3B-2)/3R = T
Answer:
8
Step-by-step explanation:
8 - 11 = -3 :)
Answer:
3rd answer
Step-by-step explanation:
It is an open circle and it has to be less than 15 and since it is a positive it is to the right
Check the picture drawn
Consider the line segment AB,
let M be the midpoint of AB, so AM=MA
erect the perpendicular MT to AB from point M. Pick a point P on MT and join it to the points A and B
The triangles PMA and PMB are congruent from the Side Angle Side congruence postulate:
AM=MA, PM is common and m(PMA)=m(PMB)=90°, as MT is perpendicular to AB
so PA=PB