Making assumptions about where parentheses should be,
<span>Let u = -7x </span>
<span>du = -7dx </span>
<span>dv = e^(2x) dx </span>
<span>v = e^(2x)/2 </span>
<span>∫ -7xe^(2x) dx = </span>
<span>-7xe^(2x)/2 - ∫ e^(2x)/2 (-7) dx = </span>
<span>-7xe^(2x)/2 + 7e^(2x)/4 + c</span>
Answer:
Step-by-step explanation:
This is the simplest form as 17 is a prime number.
19 is a prime number. so it is the simplest form.
Step-by-step explanation:
that is only possible, if we don't need to use a 2 and a 5 (but especially the 2) to create the 1 in the middle (log(10) = log(2×5) or log (5×2) = 1).
in other words, if the 1 in the middle is just a given, and does not use any of our digits for is creation, then a solution is possible.
first of all, the upper left corner has to be log(0⁰). we cannot use the digit 0 for anything else. and 0^n (except for n = 0) is not a valid argument for a logarithm.
log(0⁰) = 0 log(2×1) = 0.3... log(9/4) = 0.35...
log(1×2) = 0.3... 1 log(3×6) = 1.26...
log(7/3) = 0.37... log(4×5) = 1.3... log(6⁹) = 7.0...
but as soon as we need to build the center 1 by log(10), which takes then away one of the 2s (as the only way to build 10 by multiplication is 2×5 or 5×2), there is no possible solution.
First substitute
(3)(4)/4
then simplify.
12/4
then solve
3
