Answer:
The standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 175760000
Step-by-step explanation:
If there are no restrictions, all numbers and letters are available to be used then. And with no restrictions, every number or letter can appear more than once.
There are 7 spaces available; 3 spaces for letters, 4 spaces for numbers
The different combination of letters and numbers then becomes,
26 × 26 × 26 × 10 × 10 × 10 × 10
This is because, all 26 letters (A to Z) can occupy the first space, the second space and the third space. And all 10 digits (0 to 9) can occupy the fourth space, the fifth space, the sixth space and the seventh space.
So, the standard issue license plates that can be produced if there are no restrictions on the letters and numbers = 26 × 26 × 26 × 10 × 10 × 10 × 10 = 175760000 different standard issue license plates.
Answer:
C. 
A. First Picture
Step-by-step explanation:
We are given the inequality, 
.
On simplifying the inequality, we get,
i.e.
i.e. 
i.e. 
So, we get the correct representations of the inequality are,
C.
A. the First Picture
(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))
Recall that
tan(<em>θ</em>) = sin(<em>θ</em>) / cos(<em>θ</em>)
so cos²(<em>θ</em>) cancels with the cos²(<em>θ</em>) in the tan²(<em>θ</em>) term:
(sin²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>))
Recall the double angle identity for cosine,
cos(2<em>θ</em>) = 2 cos²(<em>θ</em>) - 1
so the 1 in the denominator also vanishes:
(sin²(<em>θ</em>) - 1) / (2 cos²(<em>θ</em>))
Recall the Pythagorean identity,
cos²(<em>θ</em>) + sin²(<em>θ</em>) = 1
which means
sin²(<em>θ</em>) - 1 = -cos²(<em>θ</em>):
-cos²(<em>θ</em>) / (2 cos²(<em>θ</em>))
Cancel the cos²(<em>θ</em>) terms to end up with
(tan²(<em>θ</em>) cos²(<em>θ</em>) - 1) / (1 + cos(2<em>θ</em>)) = -1/2
Answer:
Rate = 1.125
New Value = 312,750
Step-by-step explanation:
A. 1/8 = 0.125
1+0.125=1.125
1.125 x Old value = New Value
B.
1.125 x 278,000 = New Value
312,750
0.17 is bigger because you compare the values of the number in each place. There is no whole number, the tenths place is equal. Then in the hundredths place you have a 6 and a 7. 6<7 so therefore 0.17> 0.165. To help yourself out u can add a 0 at the end to then more easily compare .170 to .165
