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3 years ago

Which of the following are the zeroes of the function y = 3 ( x − a )( x + b )y = 3 ( x - a )( x + b ) in terms of a a and bb ?

Mathematics

2 answers:

Murljashka [212]3 years ago

8 0

I believe the answer is <span> bb</span>

FinnZ [79.3K]3 years ago

4 0

<span>( x - a )( x + b )

It would help if you put them separate from each other better.</span>

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Lady_Fox [76]

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Parameterize $S$ by

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with $0\le u\le1$ and $0\le v\le2\pi$ .

Take the normal vector to $S$ to be

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$\nabla\times\vec F(x,y,z)=(1-x)\,\vec\imath-\vec\jmath+(z-2)\,\vec k$

Then the line integral is equivalent to

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$=\displaystyle\int_0^{2\pi}\int_0^1\bigg((1-u\cos v)\,\vec\imath-\vec\jmath+(u\sin v+4)\,\vec k\bigg)\cdot\bigg(-u\,\vec\jmath+u\,\vec k\bigg)\,\mathrm du\,\mathrm dv$

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3 years ago

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bagirrra123 [75]

Answer:

x=4

Step-by-step explanation:

12x-48 12*(4)

12=0

x=4=0

Add 4 to both sides of the equation

So x=4

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Kaylis [27]

Answer:

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Step-by-step explanation:

that's what I got, I apologize if it's incorrect

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