How many dose 35 get to 56?

Three and two third divided by two

suter [353]

Answer:

1⅚

Step-by-step explanation:

(3 + ⅔) ÷ 2

11/3 ÷ 2

11/3 × 1/2

11/6

1⅚

8 0

3 years ago

PLEASE HELP ME. I WILL GIVE GIVE YOU BRAINLIEST. But only if the answers are correct

-Dominant- [34]

Answer:

12 I wanna say!!!!!!!!!!!!

8 0

3 years ago

Read 2 more answers

On a map the distance between Juneau and Fairbanks is 5 inches. The approximate distance is 625 miles. The distance between Denv

maks197457 [2]

Answer:

The answer for this question is 2,437.5 or rounded 2,438.

Step-by-step explanation:

5 goes into 19.5, 3.9 times to get that take 19.5÷5 to get 3.9. Then take 625×3.9 to get the total of 2,437.5 miles for your answer.

5 0

3 years ago

The absolute value of a number is the distance it is from 0. The bug is currently to the left of 0 and the absolute value of its

Ksenya-84 [330]

Answer:

- 4

Step-by-step explanation:

The absolute value of a number renders a number positive regardless of the preceeding sign. Therefore, either a number is positive or negative, the absolute value of such number will be positive.

In a number line, 0 is the midpoint and values to the left of 0 are negative, while those to the right are positive.

For the scenario, above, the bug is to the left of 0 and has an absolute value of 4 ;

The current position of the number line will be 4 (absolute value) places to the left of 0 which is - 4 (negative numbers are in the left).

6 0

3 years ago

The expression (secx + tanx)2 is the same as _____.

trapecia [35]

Answer:

The expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

Solution:

From question, given that $\bold{(\sec x+\tan x)^{2}}$

By using the trigonometric identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$ the above equation becomes,

$(\sec x+\tan x)^{2} = \sec ^{2} x+2 \sec x \tan x+\tan ^{2} x$

We know that $\sec x=\frac{1}{\cos x} ; \tan x=\frac{\sin x}{\cos x}$

$(\sec x+\tan x)^{2}=\frac{1}{\cos ^{2} x}+2 \frac{1}{\cos x} \frac{\sin x}{\cos x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

$=\frac{1}{\cos ^{2} x}+\frac{2 \sin x}{\cos ^{2} x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

On simplication we get

$=\frac{1+2 \sin x+\sin ^{2} x}{\cos ^{2} x}$

By using the trigonometric identity $\cos ^{2} x=1-\sin ^{2} x$ ,the above equation becomes

$=\frac{1+2 \sin x+\sin ^{2} x}{1-\sin ^{2} x}$

By using the trigonometric identity $(a+b)^{2}=a^{2}+2ab+b^{2}$

we get $1+2 \sin x+\sin ^{2} x=(1+\sin x)^{2}$

$=\frac{(1+\sin x)^{2}}{1-\sin ^{2} x}$

$=\frac{(1+\sin x)(1+\sin x)}{1-\sin ^{2} x}$

By using the trigonometric identity $a^{2}-b^{2}=(a+b)(a-b)$ we get $1-\sin ^{2} x=(1+\sin x)(1-\sin x)$

$=\frac{(1+\sin x)(1+\sin x)}{(1+\sin x)(1-\sin x)}$

$= \frac{1+\sin x}{1-\sin x}$

Hence the expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

8 0

3 years ago

How many dose 35 get to 56? ​

How many dose 35 get to 56?