8.6 would be in one but you could round your answer to 9 or just keep it that way

We have to find out the value of the fraction.
<u>Let us assume that:</u>

<u>We can also write it as:</u>




<u>Comparing </u>the given <u>equation</u> with <u>ax² + bx + c = 0,</u> we get:

<u>By quadratic formula:</u>







<u>But </u><u>"</u><u>x"</u><u> cannot be negative. Therefore:</u>

So, the value of the fraction is 1 + √2.
Answer:
18x^2+6
Step-by-step explanation:
2(9x^2+3)
multiply each term in parentheses by 2
2 x 9x^2+2 x 3
calculate product
18x^2+2 x 3
multiply numbers
18x^2+6