Question

Help! I really really need this​

Answer 1

Answer:

A point E is taken on OB such that OC= OE and draw EF perpendicular to OX or OX' .

Since,

< YOB= <XOA

Therefore, < OEF=<COD

Now, from the right- angled traingle EOF and right-angled traingle COD we get ,< OEF= < COD and OE= OX

hence, traingle EOF= Triangle COD ( Congruent)

Therefore, EF=OD, OF= DC, And OE= OC