3 years ago

Help! I really really need this

Mathematics

1 answer:

NeTakaya3 years ago

8 0

Answer:

A point E is taken on OB such that OC= OE and draw EF perpendicular to OX or OX' .

Since,

< YOB= <XOA

Therefore, < OEF=<COD

Now, from the right- angled traingle EOF and right-angled traingle COD we get ,< OEF= < COD and OE= OX

hence, traingle EOF= Triangle COD ( Congruent)

Therefore, EF=OD, OF= DC, And OE= OC

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Help! I really really need this​

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