Answer:
20 +/- $6.74
= ( $13.26, $26.74)
The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x1-x2 +/- margin of error
x1-x2 +/- z(√(r1^2/n1 + r2^2/n2)
Given that;
Mean x1 = $200
x2 = $180
Standard deviation r1 = $22.50
r2 = $18.30
Number of samples n1 = 60
n2 = 40
Confidence interval = 90%
z(at 90% confidence) = 1.645
Substituting the values we have;
$200-$180 +/-1.645(√(22.5^2/60 +18.3^2/40)
$20 +/- 6.744449847374
$20 +/- $6.74
= ( $13.26, $26.74)
The 90% confidence interval for the difference in average amounts spent on textbooks (math majors - English majors) is ( $13.26, $26.74)
I think it's A because of PEMDAS so you multiply 8 by n-3
Answer:
5/6
Step-by-step explanation:
5/1 cakes shared by 6/1 people. To divide, we can freeze flip and multiply the fractions to get to 5/1 * 1/6 = 5/6 cakes per person. Let me know if this helps.
Answer:
C
Step-by-step explanation:
C
To solve the question we use the compound interest formula which is given by:
A=p(1+r)^(nt)
where:
A=future value
p=principle
r=rate
n=number of terms
t=time
thus plugging in the values in the formula we shall have:
A=835(1+0.04)^(4t)
simplifying this we get the sequence:
A=835(1.040)^(4t)
Thus the answer to the sequence will be:
A=835(1.040)^(4t)
