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max2010maxim [7]
3 years ago
10

11x + x helppp plzzz

Mathematics
1 answer:
Juliette [100K]3 years ago
4 0
This answers would be 12x
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I need help with this ASAP PLZ!!!!!!!!
Rina8888 [55]

Answer:

4. y = 2x -6

5. y = -x + 3

6. y = -\frac{1}{3}x - 1

7. m= -4 and b=3

8. m= 1 and b=-7

9. y = 0.08x + 3

10. y= 3x - 19

11. y= -3x + 5

Step-by-step explanation:

Use the equation y = mx + b; where m is the slope and b is the y-intercept

4. given: m = 2 and y-int = -6; plug into equation

y = mx + b

y = 2x -6

5. given: m = -1 and y-int = 3; plug into equation

y = mx + b

y = -x + 3

6. given: m = -1/3 and y-int = -1; plug into equation

y = mx + b

y = -\frac{1}{3}x - 1

7. given: y=-4x+3; slope m and y-intercept b are

m= -4

b=3

8. given: y=x-7; slope m and y-intercept b are

m= 1

b=-7

9.  the monthly of $3 is fixed or starts the month; which is the y-intercept (another way to say is it is at 0 minutes) so b = 3.  Now the rate is $0.08 per minutes and the rate is the same as the slope, m= 0.08

Using equation y=mx+b; substitute

y = 0.08x + 3

10.  Given: (6,-1) and m= 3

use y=mx+b; substitute the y point into equation

-1 = 3x + b; substitue the x point into equation

-1 = 3(6) + b; solve for b

b = -19; now plug back into equation

y = mx + b or y= 3x - 19

11.  Given: (2,-1) and m= -3

use y=mx+b; substitute the y point into equation

-1 = -3x + b; substitue the x point into equation

-1 = -3(2) + b; solve for b

b = 5; now plug back into equation

y = mx + b or y= -3x + 5

8 0
3 years ago
△ABC is a right triangle with right angle C. Side AC¯¯¯¯¯¯¯¯ is 6 units longer than side BC¯¯¯¯¯¯¯¯. If the hypotenuse has lengt
Vladimir [108]

Given:

In △ABC is a right angle triangle.

AC is 6 units longer than side BC.

Hypotenuse=2\sqrt{17}

To find:

The length of AC.

Solution:

Let the length of BC be x.

So, Length of AC = x+6

According to the Pythagoras theorem, in a right angle triangle

Hypotenuse^2=Base^2+Perpendicualar^2

△ABC is a right angle triangle and AC is hypotenuse, so

(2\sqrt{17})^2=(x)^2+(x+6)^2

68=x^2+x^2+12x+36            [\because (a+b)^2=a^2+2ab+b^2]

Subtract 68 from both sides.

0=2x^2+12x+36-68

0=2x^2+12x-32

0=2(x^2+6x-16)

Divide both sides by 2.

x^2+6x-16=0

Splitting the middle term, we get

x^2+8x-2x-16=0

x(x+8)-2(x+8)=0

(x+8)(x-2)=0

x=-8,2

Side cannot be negative, so x=2 only.

Now,

AC=x+6

AC=2+6

AC=8

Therefore, the length of AC is 8 units.

6 0
3 years ago
Evaluate the following expression for a = 12 and b = 4 2a/2b
Schach [20]

Answer:

3

Step-by-step explanation:

1. Substitute 12 for a and 4 for b in the equation:  (2(12)) / (2(4))

2. Multiply:  24/8 = 3

7 0
2 years ago
Frieda friendly works for a local car dealership. She noticed that 3/4 of the cars are sedans and that half of them are white. W
vodomira [7]
1.7 of the cars are white sedans
6 0
3 years ago
Read 2 more answers
Mr. williams physical education class lasts 7/8 hour. Instructions are 1/5 of that time, how many minutes are NOT spent on instr
melomori [17]
37/40 but you should probably wait for a second opinion because i bad at math
6 0
4 years ago
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