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PilotLPTM [1.2K]
3 years ago
11

A spacecraft heading for Pluto will take pictures of several other planets on its way. The above equation gives the distance, dd

d, in millions of kilometers, of the craft from its first photo opportunity with Mars in terms of the time, ttt, in days. What is the meaning of the 212212212 in this equation
Physics
1 answer:
ioda3 years ago
5 0

Answer:

The maximum number of days for the trip

Explanation:

Given

d = 1.06(212 - t) --- Missing Equation

Required

What does d represent?

From the question, we understand that t represent the number of days;

So, by default 212 represent days

Going further:

For the equation, d = 1.06(212 - t) to be valid; the value of t must be within the interval;

0 \le t \le 212

When t = 0;

that is the beginning of the journey

As t increases;

212 - t decreases

Until the point where t = 212,

This signifies the end of the journey

So: 212 - t indicates a particular day between 0 and 212.

Hence, 212 represents the maximum number of days for the trip.

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Male Rana catesbeiana bullfrogs are known for their loud mating call. The call is emitted not by the frog's mouth but by its ear
Sidana [21]

Answer:

The amplitude of the eardrum's oscillation is 6.65×10^-13 m.

Explanation:

Given data:

The sound has a frequency of 262 Hz

The sound level is 84 dB

The air density is 1.21 kg/m^3

The speed of sound is 346 m/s

Solution:

As, Intensity of sound is given by,

I = Io×10^(s/10 db)

I = 2×π^2×ρ×v×f^2×Sm^2

Thus,

Sm = √(Io×10^(s/10 db)) / √( 2×π^2×ρ×v×f^2)

Now, put the values,

Sm = √( 10^-12 × 10^(84/10) ) / √( 2×(3.14)^2×1.21×346×(262)^2 )

Sm = √(2.51×10^-4 / 5.66×10^8)

Sm = √0.443×10^-12

Sm = 6.65×10^-13 m.

8 0
3 years ago
the net force on a vehicle is accelerating at a rate of 1.5 milliseconds is 1800 Newtons. What is the mass of the vehicles neare
Goryan [66]

Answer:

The mass is 1200 kilograms

Explanation:

Because Force is equal to mass times acceleration (F=m×a)

F=m×a

1800N=?×1.5

1800÷1.5=1200

1800N=1200Kg×1.5

7 0
4 years ago
Please help 1-9 15 points
Serjik [45]

Answer:

<h2><u>3. The Sputnik orbitted at approximately 577.1 km above the surface of the Earth.  </u></h2><h2><u>4.First Successful U.S. Rocket Launch into Space was The Jupiter C</u></h2>

Explanation:

The first two are already answered 5-9 I cannot answer because I have not watched "October sky video" and I don't know who homer and the boys are<em>.</em>

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5 0
3 years ago
Two wheel gears are connected by a chain. The larger gear has a radius of 8 centimeters and the smaller gear has a radius of 3 c
dezoksy [38]

Answer:

B.The linear velocity of the gears is the same. The linear velocity is 432π centimeters per minute.

Explanation:

As we know that the small gear completes 24 revolutions in 20 seconds

so the angular speed of the smaller gear is given as

\omega = 2\pi\frac{24}{20}

\omega = 2.4\pi rad/s

Now we know that the tangential speed of the chain is given as

v = r \omega

so we have

v = (3 cm)(2.4\pi)

v = 7.2 \pi cm/s

v = 432\pi cm/min

Since both gears are connected by same chain so both have same linear speed and hence correct answer will be

B.The linear velocity of the gears is the same. The linear velocity is 432π centimeters per minute.

8 0
4 years ago
Using the conversion factor from eV (electron volts) to joules, determine which energy line for an electron dropping from one en
Tom [10]

Explanation:

Wavelength in an emission spectrum,  \lambda=435\ nm=435\times 10^{-9}\ m  

The energy of an electron is given by :

E=\dfrac{hc}{\lambda}

Where

h is the Planck's constant

c is the speed of light

For 435 nm, the energy of the electron will be :

E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8\ m/s}{435\times 10^{-9}}

E=4.57\times 10^{-19}\ J

We know that 1\ eV=1.6\times 10^{-19}\ J

So, E=\dfrac{4.57\times 10^{-19}}{1.6\times 10^{-19}}

So, E = 2.86 eV

The energy of the electron dropping from one energy level is 2.86 eV. We know that,

\dfrac{hc}{\lambda}=E_{n_2}-E_{n_1}

From the given energy levels :

E_5-E_2=-0.544-(-3.403)

E_5-E_2=2.859\ eV

So, the transition must be from E₅ to E₂. Hence, this is the required solution.                                             

5 0
4 years ago
Read 2 more answers
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