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RSB [31]
3 years ago
10

2. A 2.5 meter-long wave travels at 1 m/s towards a fixed boundary. After 2 seconds, how does the wave appear?

Physics
1 answer:
Elan Coil [88]3 years ago
6 0

Answer:

Since incident wave and its reflected part in opposite phase superimpose on each other

So correct answer will be

Option B

Explanation:

Here we know that the wave reflection is done by rigid boundary

So when wave is reflected by the boundary then its phase is reversed by 180 degree

so the reflected wave is in reverse phase from the boundary

so we can superimpose the reflected part with incident wave to dine the resultant wave

So the phenomenon is given as follow

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A 2,000 kg car is parked at the top of a 30 m high hill. what is its potential energy?
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The earth has a vertical electric field at the surface,pointing down, that averages 102 N/C. This field is maintained by various
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Answer:

q  =  -461532.5 \ C

Explanation:

From the question we are told that

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=>   E  A  =  \frac{q}{\epsilon_o }

Given that  the electric field is pointing downward  , the equation become

    - E  A  =  \frac{q}{\epsilon_o }

Here   q is the excess charge on the surface of the earth

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     A  =  4\pi r^2

Where r is the radius of the earth which has a value r = 6.3781*10^6 m

 substituting values

    A  = 4 * 3.142  *   (6.3781*10^6 \ m)^2

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So

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Here \epsilon_o s the permitivity of free space with value

          \epsilon_o  =  8.85*10^{-12} \  m^{-3} \cdot kg^{-1}\cdot  s^4 \cdot A^2

substituting values

     q  =  -102  * 5.1128 *10^{14}  *  8.85 *10^{-12}

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6 0
3 years ago
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Musya8 [376]

Answer:

10A

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kolezko [41]

The rock strike the water with the speed of 15.78 m/sec.

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