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marusya05 [52]
3 years ago
9

Please help 1-9 15 points

Physics
1 answer:
Serjik [45]3 years ago
5 0

Answer:

<h2><u>3. The Sputnik orbitted at approximately 577.1 km above the surface of the Earth.  </u></h2><h2><u>4.First Successful U.S. Rocket Launch into Space was The Jupiter C</u></h2>

Explanation:

The first two are already answered 5-9 I cannot answer because I have not watched "October sky video" and I don't know who homer and the boys are<em>.</em>

I Hope This helps

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What is first class lever ? can you pease say where is does the fulcrum ,load and effort​
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In first class lever the fulcrum lies between the effort and the load the effort lies on the left side and load lies on the right side .

Explanation:

hope this helps

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3 years ago
What is the time required for an object starting
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(3) 10.1 second Using equation of motion 500 = (0.5)(9.81)t^2. Rearranging, t = sqrt(1000/9.81) = 10.1s
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<h3>stay safe healthy and happy.</h3>

7 0
3 years ago
two circular plates, each with a radius of 8.22 cm, have equal and opposite charges of magnitude 3.052 μc. calculate the electri
PtichkaEL [24]

If the separation distance is doubled, then the electric field decreases by a factor of 4.

<h3>What is the electric field strength?</h3>

We know that the electric field strength is known to depend on the magnitude of the charge and the distance of separation. We know that the electric field refers to the region in which the influence of a charge is felt. Recall that a charge is a specie that is positively or negatively charged. The charge on a specie must always be shown by its sign.

We know that the electric field is the region in space where the influence of a charge can be felt. If a charge is placed in the vicinity of another charge, the second charge would experience a force due to the presence of the first charge. This is because the second charge was brought into the electric field of the first charge.

Thus we know that;

E = Kq/r^2

Where;

E = electric field strength

q = magnitude of charge

r = distance of separation

Now;

E = 9.0* 10^9 * 3.052 * 10^-6/(8.22 * 10^-2)^2

E = 4 N/C

Given that the electric filed strength is inversely proportional to the distance of separation, when the distance between the charges is doubled, the electric field decreases by a factor of 4.

Learn more about electric field strength:brainly.com/question/15170044?

#SPJ1

7 0
1 year ago
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