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Mariulka [41]
3 years ago
12

A ​$320 suit is marked down by 10​%. Find the sale price. Please help

Mathematics
2 answers:
Jobisdone [24]3 years ago
5 0

Answer:

$288

Step-by-step explanation:

320 * 0.1 = 32

320-32= 288

puteri [66]3 years ago
4 0

Answer: it costs $288, I hope this answers your question:)

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Colin buys a tv for £800. It depreciates at a rate of 1% per year. How much will it be worth in 2 years? Give your answer to the
bezimeni [28]

Answer: £784.08

Step-by-step explanation:

First find 1% of 800, which is 800/100=£8

800-8= £792 after 1 year

find 1% of 792, which is 792/100=£7.92

792-7.92= £784.08

6 0
3 years ago
I need the answer for this question
Scrat [10]

Answer:

z=-13.9

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7 0
3 years ago
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If a projectile is launched vertically upward from 800 ft above the ground with an initial velocity of 80 ft per second, its hei
tiny-mole [99]

Hello!

10 seconds to return to the ground.

7 seconds to reach 576 feet above the ground.

Find the amount of time taken to reach the ground by setting the equation equal to 0:

0 = -16t² + 80t + 800

Factor out -16 from the equation:

0 = -16(t² - 5t - 50)

Factor the terms inside of the parenthesis:

0 = -16(t - 10)(t + 5)

Find the zeros:

t - 10 = 0

t = 10

t + 5 = 0

t = -5

Time can only be positive in this instance, so the correct answer is 10 sec.

Find the time by substituting in 576 for the height:

576 = -16t² + 80t + 800

Subtract 800 from both sides:

-224 = -16t² + 80t

Rearrange:

0 = -16t² + 80t + 224

Simplify:

0 = -16(t² - 5t - 14)

0 = -16(t - 7)(t + 2)

t = 7 seconds.

8 0
3 years ago
22. Determine the value of c so that the line
tiny-mole [99]

Answer:

If the lines BC and DE are parallel, the value of c is c=-2

Step-by-step explanation:

We are given line segment BC with end points B(2, 2) and C(9,6) and line segment DE with endpoints  D(c, -7) and E(5, -3).

Using slope formula: Slope=\frac{y_2-y_1}{x_2-x_1} we can find point c

When 2 lines are parallel there slope is same.

So, Slope of line BC =Slope of Line DE

\frac{y_2-y_1}{x_2-x_1}=\frac{y_2-y_1}{x_2-x_1}

We have:

x_1=2, y_1=2, x_2=9, y_2=6 \ for \ line \ BC \ and \\\x_1=c, y_1=-7, x_2=5, y_2=-3 \ for \ line \ DE \

Putting values and finding c

\frac{6-2}{9-2}=\frac{-3-(-7)}{5-c}\\ \frac{4}{7}=\frac{-3+7}{5-c} \\ \frac{4}{7}=\frac{4}{5-c} \\Cross \ multiply:\\4(5-c)=4*7\\20-4c=28\\-4c=28-20\\-4c=8\\c=\frac{8}{-4}\\c=-2

So, If the lines BC and DE are parallel, the value of c is c=-2

8 0
3 years ago
Consider the table for the exponential function, LaTeX: p\left(x\right)=2^xp ( x ) = 2 x, shown below. Calculate the Average Rat
Mice21 [21]

Answer:

15

Step-by-step explanation:

To find the average rate if change of the exponential function between the interval [2, 6], use the formula, m = \frac{p(b) - p(a)}{b - a}

Where,

a = 2, p(2) = 4

b = 6, p(6) = 64

Plug in the above values into the formula:

m = \frac{64 - 4}{6 - 2}

m = \frac{60}{4}

m = 15

Average rate of change is 15

3 0
3 years ago
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