v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
Answer:
-70x + 21
Step-by-step explanation:
1-8(10x-3)
-7(10x-3)
Use distributive property
-70x + 21
(This is how we learned to do it in my school)
To solve this, you can substitute the second equation into the first.
It becomes 2x-(2x+3)=7
Solve from here!
You get -3=7. Not possible. Therefore there is no solution to this system.
System is inconsistent. Hope this helps.
