All categories

3 years ago

Please Help!

Mathematics

1 answer:

vovikov84 [41]3 years ago

3 0

Answer:

Step-by-step explanation:

We can use triangle inequality, let AC = x:

x+4 > 5

x+5 > 4

9 > x

Simplifying:

x>1

x>-1

9>x

Thus: 9>x>1

So the Largest whole number is 8

You might be interested in

What does this mean 3^4

nirvana33 [79]

3^4 means 3 to the 4th power.
This means that you would multiply 3 by itself 4 times
It would look like this...3*3*3*3
3^4=81

4 0

2 years ago

Read 2 more answers

What is the equation of the line that passes through the points (4, –1) and (3, 5)?

uysha [10]

Answer:

(4, -1) (3, 5) In this problem, we use the formula y2 - y1 over x2 - x1.

Step-by-step explanation:

Step 1: Plug In--> 5 - (-1)

3 - 4

Step 2: Simplify. --> 6

-1

Answer: -6

5 0

2 years ago

Please just help with these questions!

devlian [24]

5/7= -----------

0.714285

Convert the fraction to a decimal by dividing the numerator by the denominator.

6/10= 0.6

Convert the fraction to a decimal by dividing the numerator by the denominator.

16/20= 0.8

Convert the fraction to a decimal by dividing the numerator by the denominator.

9/10= 0.9

Convert the fraction to a decimal by dividing the numerator by the denominator.

3 0

2 years ago

10-2(2x+1)=4(x-2)solve each equation for x graph your Solution on a number line

stepladder [879]

Answer:

No solution

Step-by-step explanation:

Actually, you have only one equation here. We will solve it for x.

Performing the indicated multiplication, we obtain:

10-2(2x+1)=4(x-2) => 10 - 4x - 2 = 4x - 8, or 10 - 2 = -8. This can never be true, so this equation has no solution.

6 0

3 years ago

Read 2 more answers

Find the approximate perimeter of ABC plotted below.

maksim [4K]

Answer:

B. 21.2

Step-by-step explanation:

Perimeter of ∆ABC = AB + BC + AC

A(-4, 1)

B(-2, 3)

C(3, -4)

✔️Distance between A(-4, 1) and B(-2, 3):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB = \sqrt{(-2 - (-4))^2 + (3 - 1)^2} = \sqrt{(2)^2 + (2)^2)}$

$AB = \sqrt{4 + 4}$

$AB = \sqrt{16}$

AB = 4 units

✔️Distance between B(-2, 3) and C(3, -4):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 - (-2))^2 + (-4 - 3)^2} = \sqrt{(5)^2 + (-7)^2)}$

$BC = \sqrt{25 + 49}$

$BC = \sqrt{74}$

BC = 8.6 units (nearest tenth)

✔️Distance between A(-4, 1) and C(3, -4):

$AC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AC = \sqrt{(3 - (-4))^2 + (-4 - 1)^2} = \sqrt{(7)^2 + (-5)^2)}$

$AC = \sqrt{47 + 25}$

$AC = \sqrt{74}$

AC = 8.6 units (nearest tenth)

Perimeter of ∆ABC = 4 + 8.6 + 8.6 = 21.2 units

8 0

3 years ago