2 years ago

(x+1).(x/2 +2).(x/3+3).(x/4+4).(x/5+5)

Mathematics

1 answer:

koban [17]2 years ago

6 0

Answer:

Please see the attached picture below to understand the steps I've typed to get to the final solution.

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If there are 1500 guests, only 1 of them brought a coupon for free admission to the carnival?

wlad13 [49]

So 1/50 brought the pass
x out 1500
1/50 = x/1500
cross multiply
1500 = 50x
divide both sides by 50
30 = x

You can expect for 30 out of the 1,500 to receive free admissions.

Hope this helps

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3 years ago

The perimeter of a rectangle is 126 inches. The length is 7 less than 4 times the width. Find the dimensions of the rectangle. P

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2 years ago

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olchik [2.2K]

Answer:

4 and 3 <------- That's the set I believe!

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2 years ago

Read 2 more answers

A sequence is constructed according to the following rule: its first term is 7, and each next term is one more than the sum of t

Iteru [2.4K]

Answer:

Step-by-step explanation:

According to the described rule, we have

$a_1=7\\ \\a_1^2=7^2=49\Rightarrow a_2=4+9+1=14\\ \\a_2^2=14^2=196\Rightarrow a_3=1+9+6+1=17\\ \\a_3^2=17^2=289\Rightarrow a_4=2+8+9+1=20\\ \\a_4^2=20^2=400\Rightarrow a_5=4+0+0+1=5\\ \\a_5^2=5^2=25\Rightarrow a_6=2+5+1=8\\ \\a_6^2=8^2=64\Rightarrow a_7=6+4+1=11\\ \\a_7^2=11^2=121\Rightarrow a_8=1+2+1+1=5\\ \\\text{and so on...}$

We can see the pattern

$a_5=a_8=a_{11}=a_{14}=...=5\\ \\a_6=a_9=a_{12}=a_{15}=...=8\\ \\a_7=a_{10}=a_{13}=a_{16}=...=11$

In other words, for all $k\ge 2$

$a_{3k-1}=5\\ \\a_{3k}=8\\ \\a_{3k+1}=11$

Now,

$a_{2018}=a_{3\cdot 673-1}=5$

7 0

3 years ago