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azamat
3 years ago
6

Write a balanced nuclear equation for the alpha decay of titanium-45.

Chemistry
1 answer:
schepotkina [342]3 years ago
6 0

Explanation:

20984Po→20582Pb+42α

4520Ca→4521Sc+0-1e+00ν

Explanation:

The alpha decay of polonum-209, which consists of the emission of an alpha particle, will leave behind the atom of a different element.

Notice that the identity of the element changes after the decay. This means that you're dealing with a nuclear transmutation, a process that converts an atom of a given element into an atom of a different element.

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, Hydrocarbons are compounds that contain(1) carbon, only(2) carbon and hydrogen, only(3) carbon, hydrogen, and oxygen, only(4)
Firdavs [7]
Hydrocarbons are compounds formed by only hydrogen atoms and carbon.

Answer (2)

hope this helps!
4 0
3 years ago
Which statement describes how the binary ionic compound KBr is named?
pshichka [43]

Which statement describes how the binary ionic compound KBr is named? The metal is named first, and the name is unchanged. Which of these is a property of a substance that is composed of atoms that are held together by ionic bonds?

4 0
3 years ago
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Compare the volume of 14.1 g of helium to 14.1 g of argon gas (under identical conditions).
s2008m [1.1K]
The Volumes can be calculated from Masses by using following Formula,

                                        Density  =  Mass / Volume
Solving for Volume,
                                        Volume  =  Mass / Density

Mass of Both Gases  =  14.1 g

Density of Argon at S.T.P  =  1.784 g/L

Density of Helium at S.T.P  =  0.179 g/L

For Argon:
                                        Volume  =  14.1 g / 1.784 g/L

                                        Volume  =  7.90 L

For Helium:
                                        Volume  =  14.1 g / 0.179 g/L

                                        Volume  =  78.77 L
4 0
3 years ago
Consider a certain type of nucleus that has a half-life of 32 min. calculate the percent of original sample of nuclides remainin
Irina18 [472]
t1/2 = ln 2 / λ = 0.693 / λ
Where t1/2 is the half life of the element and λ is decay constant.

32 = 0.693 / λ 
λ   = 0.693 / 32          (1) 

Nt = Nο eΛ(-λt)          (2)

Where Nt is atoms at t time, λ is decay constant and t is the time taken.
t = 1.9 hours = 1.9 x 60 min

From (1) and (2),


Nt = Nο e⁻Λ(0.693/32)*1.9*60
Nt =  0.085Nο 

Percentage = (Nt/Nο) x 100%
                   = (0.085Nο/Nο) x 100%
                   = 8.5%

Hence, Percentage of remaining atoms with the original sample is 8.5%

8 0
4 years ago
What elements are present in sugars?
miss Akunina [59]
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6 0
3 years ago
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