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3 years ago

Write a balanced nuclear equation for the alpha decay of titanium-45.

Chemistry

1 answer:

schepotkina [342]3 years ago

6 0

Explanation:

20984Po→20582Pb+42α

4520Ca→4521Sc+0-1e+00ν

Explanation:

The alpha decay of polonum-209, which consists of the emission of an alpha particle, will leave behind the atom of a different element.

Notice that the identity of the element changes after the decay. This means that you're dealing with a nuclear transmutation, a process that converts an atom of a given element into an atom of a different element.

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Iron metal reacts with elemental oxygen to form rust according to the unbalanced reaction, Fe(s) + O2(g) → Fe2O3(s),. What is th

pochemuha

Answer:

c. 3

Explanation:

The unbalanced reaction expression is given as:

Fe + O₂ → Fe₂O₃

To balance the expression gives the coefficient of oxygen.

Assign the coefficients a,b, c and use a mathematical approach to solve this problem:

aFe + bO₂ → cFe₂O₃

Conserving Fe: a = 2c

O: 2b = 3c

Now let c = 1, a = 2, b = $\frac{3}{2}$

Multiply through by 2,

a = 4, b = 3 and c = 2

4Fe + 3O₂ → 2Fe₂O₃

The coefficient of O₂ is 3

3 0

2 years ago

A movable piston traps 0.205 moles of an ideal gas in a vertical cylinder. If the piston slides without friction in the cylinder

Mazyrski [523]

Answer : The work done on the gas will be, 418.4 J

Explanation :

First we have to calculate the volume at 270°C.

$PV_1=nRT$

where,

P = pressure of gas = 1 atm

$V_1$ = volume of gas = ?

T = temperature of gas = $270^oC=273+270=543K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_1=0.205mol\times 0.0821L.atm/mol.K\times 543K$

$V_1=9.12L$

Now we have to calculate the volume at 24°C.

$PV_2=nRT$

where,

P = pressure of gas = 1 atm

$V_2$ = volume of gas = ?

T = temperature of gas = $24^oC=273+24=297K$

n = number of moles of gas = 0.205 mol

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the ideal gas equation, we get:

$(1atm)\times V_2=0.205mol\times 0.0821L.atm/mol.K\times 297K$

$V_2=4.99L$

Now we have to calculate the work done.

Formula used :

$w=-p\Delta V\\\\w=-p(V_2-V_1)$

where,

w = work done

p = pressure of the gas = 1 atm

$V_1$ = initial volume = 9.12 L

$V_2$ = final volume = 4.99 L

Now put all the given values in the above formula, we get:

$w=-p(V_2-V_1)$

$w=-(1atm)\times (4.99-9.12)L$

$w=4.13L.artm=4.13\times 101.3J=418.4J$

conversion used : (1 L.atm = 101.3 J)

Therefore, the work done on the gas will be, 418.4 J

6 0

3 years ago

ASAP<br>what is an electron cloud

Bad White [126]

Explanation:

An electron cloud is the region of space that surrounds the nucleus of an atom under the nucleus of the negatively charged sub-atomic particles.

An atoms is made up of some particles.
The proton is positively charged and it is located in the nucleus of an atom.
The neutrons do not carry any charges and occupies the nucleus with protons.
Electrons are the negatively charged particles outside the nucleus.
The electron cloud is portion of an atom with greatest probability of finding an electron.

Learn more:

Electron cloud brainly.com/question/1832385

#learnwithBrainly

8 0

3 years ago

Dogs use the same glycolysis and cellular processes as humans use to produce ATP. A young dog has never had much energy. He is b

scZoUnD [109]

Answer:

<h2>Dog's mitochondria lack the transport protein that transport pyruvate ( end product of glycolysis) across the outer mitochondrial membrane .</h2>

Explanation:

1. As given here that dog's mitochondria can use only fatty acids and also amino acids for their respiration, and as compared to others, Dong's cell produce more lactate then normal, this indicate that his mitochondrial membrane is different then others.

2. The aerobic phases of cellular respiration in eukaryotes occur within mitochondria. These aerobic phases are the TCA Cycle and the electron transport chain. Glycolysis occurs in the cytoplasm and the products of glycolysis enter into the mitochondria to continue cellular respiration.

3. These condition shows that dog's mitochondria lack the transport protein of mitochondria that moves pyruvate across the outer mitochondrial membrane.

3 0

3 years ago

2C_H. + 702 — 400, + 6H2O

astra-53 [7]

Balanced Eqn

By the Balanced eqn

60g ethane requires 7x32= 224g oxygen

here ethane is in excess.oxygen will be fully consumed

hence

300g oxygen will consume

⋅

300

224

80.36

ethane

leaving (270-80.36)= 189.64 g ethane.

By the Balanced eqn

60g ethane produces 4x44 g CO2

hence amount of CO2 produced =

⋅

80.36

235.72

and its no. of moles will be

235.72

=5.36 where 44 is the molar mass of Carbon dioxide

hope this helps

6 0

3 years ago