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Phantasy [73]
4 years ago
13

Consider a certain type of nucleus that has a half-life of 32 min. calculate the percent of original sample of nuclides remainin

g after 1.9 hours have passed
Chemistry
1 answer:
Irina18 [472]4 years ago
8 0
t1/2 = ln 2 / λ = 0.693 / λ
Where t1/2 is the half life of the element and λ is decay constant.

32 = 0.693 / λ 
λ   = 0.693 / 32          (1) 

Nt = Nο eΛ(-λt)          (2)

Where Nt is atoms at t time, λ is decay constant and t is the time taken.
t = 1.9 hours = 1.9 x 60 min

From (1) and (2),


Nt = Nο e⁻Λ(0.693/32)*1.9*60
Nt =  0.085Nο 

Percentage = (Nt/Nο) x 100%
                   = (0.085Nο/Nο) x 100%
                   = 8.5%

Hence, Percentage of remaining atoms with the original sample is 8.5%

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Answer:

A) vinegar-acidic Baking soda-basic Tomato juice-acidic Sugar-neutral.

Explanation:

Hello,

In this case, it is widely acknowledged that vinegar is a diluted and processed form of acetic acid which is of course acidic as well as tomato juice which has a pH of about 4.2. Baking soda, which is chemically known as sodium bicarbonate has a pH greater than 7, for that is reason it is basic. Finally, sugar, is known by its neutrality, for which its pH is about 7, for that reason it is neutral. In such a way, answer is A) vinegar-acidic Baking soda-basic Tomato juice-acidic Sugar-neutral.

Regards.

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Ivanshal [37]
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\\ \tt\hookrightarrow Q=mc\Delta T

\\ \tt\hookrightarrow Q=62.1(0.0920)(322.1)

\\ \tt\hookrightarrow Q=1840.22172cal

\\ \tt\hookrightarrow Q=1840.222cal

\\ \tt\hookrightarrow Q=1840.2cal

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