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crimeas [40]
2 years ago
6

Are the cells in this image prokaryotic or eukaryotic

Chemistry
1 answer:
Bas_tet [7]2 years ago
3 0

Answer:

Prokaryotic is the answer!

Explanation:

I know this because, the nucleolus is absent in the image.

PLZ MARK AS BRAINLIEST! HOPE THIS HELPS! :)

ps: i have the same profile photo lol, love it!

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Topics: Fundamentals of electrochemistry; Electrochemical cells
irina1246 [14]

Answer:

how to help people that helps

5 0
2 years ago
Which of these is a compound?<br><br> A. Steel<br><br> B.Sugar<br><br> C.Air<br><br> D.Nitrogen
hjlf

Sugar is a compound made of carbon, hydrogen and oxygen.

8 0
3 years ago
Read 2 more answers
"Given a block of frozen salt water, how could you separate
cricket20 [7]

Answer: You could put the frozen block of ice on the stove and let it melt and eventually boil out leaving the salt behind

Explanation:

4 0
2 years ago
The element copper has 29 protons. What is the atomic number of copper?
stiks02 [169]
The atomic number of copper is 29.

Hope this helps and if it does, don't be afraid to rate my answer as well as maybe give it a "Thanks"? (Or even better a "Brainliest"). And if it’s not correct, I am sorry for wasting your time, and good luck finding the correct answer :)


8 0
2 years ago
Read 2 more answers
When a hydrogen atom makes the transition from the second excited state to the ground state (at -13.6 eV) the energy of the phot
viktelen [127]

Answer : The energy of the photon emitted is, -12.1 eV

Explanation :

First we have to calculate the 'n^{th}' orbit of hydrogen atom.

Formula used :

E_n=-13.6\times \frac{Z^2}{n^2}ev

where,

E_n = energy of n^{th} orbit

n = number of orbit

Z = atomic number  of hydrogen atom = 1

Energy of n = 1 in an hydrogen atom:

E_1=-13.6\times \frac{1^2}{1^2}eV=-13.6eV

Energy of n = 2 in an hydrogen atom:

E_3=-13.6\times \frac{1^2}{3^2}eV=-1.51eV

Energy change transition from n = 1 to n = 3 occurs.

Let energy change be E.

E=E_-E_3=(-13.6eV)-(-1.51eV)=-12.1eV

The negative sign indicates that energy of the photon emitted.

Thus, the energy of the photon emitted is, -12.1 eV

3 0
3 years ago
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