Draw the structure of an alkane or cycloalkane that has more than three but fewer than ten carbon atoms, and only primary hydrog
ens. (There are several possible structures. It is enough to draw any one of them, but you may draw two or more if you want to.)
1 answer:
Answer:
The structures are shown in the figure.
Explanation:
The primary hydrogens are those which are attached to primary carbon.
Primary carbons are the carbons which are attached to only one carbon.
Primary carbons is bonded to three hydrogens.
In order to draw such structure we will draw structures which will have carbon with three hydrogens or no hydrogens (quaternary)
The structures are shown in the figure with clear marking.
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19.927 moles are in 1.20 times atoms of phosphorus.
A mole is defined as 6.02214076 × of some chemical unit, be it atoms, molecules, ions, or others.
1 mole of any substance contain Avogadro's number of molecules so we can calculate the number of moles by dividing the provided number of atoms over Avogadro's number to obtain the number of moles .
Moles=
Moles= 1.20 X atoms ÷ 6.022 X
= 19.927
Hence, 19.927 moles are in 1.20 times atoms of phosphorus.
Learn more about moles here:
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Answer:
4.285 L of water must be added.
Explanation:
Hello there!
In this case, for this dilution-like problems, we need to figure out the final volume of the resulting solution so that we would be able to obtain the correct volume of diluent (water) to be added. In such a way, we can obtain the final volume, V2, as shown below:
Thus, by plugging in the initial molarity, initial volume and final molarity (0.587 M) we obtain:
It means we need to add:
Of diluent water.
Regards!