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Black_prince [1.1K]

2 years ago

11

lisa had 2/3 of a box of cookies .She wanted to share the box among 8of her friend .How much of a box of cookies would each frie

nd receive ?

1 answer:

Artist 52 [7]2 years ago

3 0

Answer:

Each friend would receive 1/12 cookies

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The factorization of x^2 + 3x-4 is modeled with algebra tiles

o-na [289]

Answer:

(x-1) (x+4)

Step-by-step explanation:

i used something called the box method, basically the way i got the answer is what equals 3 when added, but multiplies to make -4

5 0

3 years ago

The annual snowfall in city Ais 43.9 inches. This is 13.5 inches more than four times the snowfall in city B. Find the annual sn

Jlenok [28]

Answer:

24.475

Step-by-step explanation:

1st Divide: 43.9÷4=10.975

2nd Add 13.5: 10.975+13.5=24.475

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Hope this helps you out :)

7 0

3 years ago

James has eight coins in his pocket. All the coins are either dimes or quarters.The total value of the coins is $1.25. How many

Goshia [24]

Answer:

he has 5d+3q

Step-by-step explanation:

since every d is .10 and every q is .25 the equation can be changed to 5(.10)+3(.25) which is equal to .5+.75 which adds up to 1.25

i did this by assuming that the amount of d is 8 at first, then change one of the 8 d to a q which will give you 7d+q, then assume another d is a q which will give you 6d+2q, repeat this until the amount of d and q add up to 1.25

6 0

3 years ago

A Rasmussen Reports survey of 1,000 US adults found that 42% believe raising the minimum wage will help the economy. Construct a

vitfil [10]

Answer:

(0.3798, 0.4602)

Step-by-step explanation:

Let p be the true proportion of US adults who believe raising the minimum wage will help the economy. A point estimate for p is $\hat{p}=0.42$ and a good aproximation (because we have a large sample) for the standard deviation of $\hat{p}$ is $\sqrt{\hat{p}(1-\hat{p})/n}=\sqrt{0.42(0.58)/1000}=0.0156$ . Therefore, a 99% confidence interval for p is given by $\hat{p}\pm z_{\alpha/2}\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}$ where $\alpha=0.01$ and $z_{\alpha/2}$ is the $\alpha/2$ th quantile of the standard normal distribution, so we have, $0.42\pm z_{0.005}0.0156$ , i.e., $0.42\pm(-2.5758)(0.0156)$ or equivalently (0.3798, 0.4602).

6 0

3 years ago

Anybody can answer this for me ?

Romashka [77]

What are you supposed to be doing

7 0

3 years ago

Read 2 more answers