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trapecia [35]
3 years ago
12

4n/5=84/15 i cannot figure out this math problem for my homework!

Mathematics
1 answer:
Vinil7 [7]3 years ago
4 0
Okay so instead of dividing you will cross multiply.
4n(15)=84(5)
60n=420
420/60=7
Answer: n=7
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Find the area and circumference of a circle which is 5cm​
Nonamiya [84]

Answer: 31.416

Step-by-step explanation:

6 0
2 years ago
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Find maximum points y=11^(6x-x²) solve using derivative
Darya [45]

Answer:

\boxed{\sf \ \ \ maximum \ is \ 11^9=2357947691 \ \ \ }

Step-by-step explanation:

hello

y = 11^{(6x-x^2)}=exp((6x-x^2)ln(11))

so to know the maximum to y we can check the maximum of

f(x)=6x-x^2

f is derivable and f'(x)=6-2x

f'(x)=0 <=> x = 3

so the maximum is reached for x = 3

f(3)=18-9=9

and then

y = 11^9=2357947691

to be rigorous, we can write the variation table of y to show that there is only one maximum

hope this helps

8 0
3 years ago
Price-club sells a 12-ounce box of crackers for $2.59 and Shop Mart sells 1-1/2 pound box of crackers for $4.68. What is the uni
katen-ka-za [31]

Unit price would be the price per ounce.

Divide the total cost by the number of ounces:

Price Club : 2.59 / 12 = $0.216 per ounce

Shop Mart: 1-1/2 pounds = 1.5 x 16 = 24 ounces.

4.68 / 24 = $0.195 per ounce.

7 0
3 years ago
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Which function has a vertex on the y-axis? f(x) = (x – 2)2 f(x) = x(x + 2) f(x) = (x – 2)(x + 2) f(x) = (x + 1)(x – 2)
strojnjashka [21]

we know that

If the vertex is on the y-axis, then the x-coordinate of the vertex is equal to zero

we are going to verify the vertex of each one of the functions to determine the solution

Remember that

The equation in vertex form of a vertical parabola is equal to

y=a(x-h)^{2} +k

where

(h,k) is the vertex

if a>0 -------> the parabola open upward (vertex is a minimum)

if a -------> the parabola open downward (vertex is a maximun)

<u>case A)</u> f(x)=(x-2)^{2}

This is a vertical parabola open upward

the vertex is the point (2,0)

therefore

The function f(x)=(x-2)^{2}  does not have a vertex on the y-axis

<u>case B)</u> f(x)=x(x+2)

f(x)=x(x+2)=x^{2}+2x

convert to vertex form

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+1=x^{2}+2x+1

Rewrite as perfect squares

f(x)+1=(x+1)^{2}

f(x)=(x+1)^{2}-1

the vertex is the point (-1,-1)

therefore

The function f(x)=x(x+2) does not have a vertex on the y-axis

<u>case C)</u> f(x)=(x-2)(x+2)

f(x)=(x-2)(x+2)=x^{2}-2^{2}

f(x)=x^{2}-4

the vertex is the point (0,-4)

The x-coordinate of the vertex is equal to zero

therefore

The function f(x)=(x-2)(x+2) has a vertex on the y-axis

<u>case D)</u> f(x)=(x+1)(x-2)

f(x)=(x+1)(x-2)\\ \\f(x)= x^{2}-2x+x-2 \\ \\f(x)= x^{2} -x-2

convert to vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)+2= x^{2} -x

Complete the square. Remember to balance the equation by adding the same constants to each side.

f(x)+2+0.25= x^{2} -x+0.25

f(x)+2.25= x^{2} -x+0.25

Rewrite as perfect squares

f(x)+2.25= (x-0.50)^{2}

f(x)=(x-0.50)^{2}-2.25

the vertex is the point (0.5,-2.25)

therefore

The function f(x)=(x+1)(x-2) does not have a vertex on the y-axis

<u>the answer is</u>

f(x)=(x-2)(x+2)

6 0
3 years ago
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3. The length of a living room is 12 feet and its width is 10.5 feet. The length of the room is being
Liono4ka [1.6K]

Since you're adding x feet to the length which is 12 feet:

New area: (12+x)10.5

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