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3 years ago

9

Which statement is not true about the pattern shown?

1 answer:

adoni [48]3 years ago

4 0

Answer:3

Step-by-step explanation:2 4 6 8 12 16 24

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Random question: hows life?

kipiarov [429]

Answer:

Great! Sorta making me really tired, but altogether fine!!!

How about you sir/ma'am?

Step-by-step explanation:

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2 years ago

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the library at a certain University reported the journal prices had increased by 150% over a period of 10 years The report concl

natima [27]

1.15¹⁰=4.0456, the growth rate, so the increase is 3.0456 or 305%.

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3 years ago

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If the difference of two numbers is 7 and their product is 60, what are they?

user100 [1]

X - y = 7.....x = y + 7
x * y = 60

y(y + 7) = 60
y^2 + 7y = 60
y^2 + 7y - 60 = 0
(y + 12)(y - 5) = 0

y + 12 = 0
y = -12....not this one because it is negative

y - 5 = 0
y = 5 <===

x - y = 7
x - 5 = 7
x = 7 + 5
x = 12 <==

so ur 2 numbers are 12 and 5

4 0

2 years ago

Radical exponent definition

kaheart [24]

Answer:

a fractional exponent in which the numerator of the fractional exponent is the power of the base and the denominator of the fractional exponent is the index of the radical.

Step-by-step explanation:

3 0

1 year ago

A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

Therefore, the total number of Munchkins in original box is 24.

3 0

3 years ago