Question

When the following equilibrium process

Answer 1

Answer:

K(eq) = 15  (2 sig. figs)

Explanation:

Rxn:         CO(g)    +    2H₂(g)    ⇄   CH₃OH(l)

C(eq):    0.150M       0.360M           0.282M  

Keq = [CH₃OH(l)]/[CO(g)][H₂(g)]

= (0.282M)/(0.150M)(0.360M)²  

= 14.50617284 (calc. ans.)

= 15 (2 sig. figs.)