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SOVA2 [1]
3 years ago
6

Cyanobacteria, also known as blue-green algae, are a kind of bacteria found in lakes. These organisms make their own food throug

h photosynthesis. Small animals including mayfly larvae eat the cyanobacteria, and small fish such as yellow perch eat the larvae. The small fish provide food for larger fish, such as walleye.
Choose the level of the food pyramid that represents the energy role of cyanobacteria in the lake ecosystem.

Chemistry
2 answers:
Zina [86]3 years ago
6 0

Answer:

Explanation:

Cyanobacteria, also known as blue-green algae, are a kind of bacteria found in many lakes. These organisms make their own food through photosynthesis. Small animals, including mayfly larvae, eat the cyanobacteria. ... The small fish provide food for larger fish, such as walleye.

notka56 [123]3 years ago
3 0
It may be the third level
You might be interested in
F
Katarina [22]

The statement is true in this situation is C. The size of Ffric is the same as the size of Fapp:

From the diagram, since the body is in equilibrium, the sum of vertical forces equals zero. Also, the sum of horizontal forces equal zero.

So, ∑Fx = 0 and ∑Fy = 0

Since Fapp acts in the negative x - direction and Ffric acts in the positive x - direction,

∑Fx = -Fapp + Ffric = 0

-Fapp + Ffric = 0

Fapp = Ffric

Also, since Fgrav acts in the negative y - direction and Fnorm acts in the positive y - direction,

∑Fy = Fnorm + (-Fgrav) = 0

Fnorm - Fgrav = 0

Fnorm = Fgrav

So, we see that the size of Fapp <u>equals</u> size of Ffric and the size of Fnorm <u>equals</u> the size of Fgrav.

So, the correct option is C

The statement which is true in this situation is C. The size of Ffric is the same as the size of Fapp.

Learn more about equilibrium of forces here:

brainly.com/question/12980489

5 0
2 years ago
C6H12O6 + 6 O2 --&gt; 6 CO2 + 6 H2O + energy In the reaction listed above, 1 molecule of glucose reacts with 6 molecules of oxyg
kirill115 [55]

Answer:

  • Third choice:<em> energy present in the glucose and oxygen that is not needed for the formation of carbon dioxide and water is released to form energy/ATP.</em>

Explanation:

<u>1) Chemical equation (given):</u>

  • C₆H₁₂O₆ + 6 O₂ --> 6 CO₂ + 6 H₂O + energy

<u>2) Chemical potential energy:</u>

Each compound stores chemical potential energy.  This energy is stored in the chemical bonds.

Due to every substance has its own unique chemical potential energy, when a chemical reaction takes plase, yielding to the change of some substances, some energy is absorbed (when bonds are formed) and some energy is released (when bonds are broken).

<u>3) Conservation of energy:</u>

Then, if the sum of the bond energies of the final products is less than the sum of the bond energies of the reactants, the<em> law of conservation of energy</em> rules that the difference between the total energies of the products and reactants must be released to the surroundings.

That is what is happening in the given reaction:

  • C₆H₁₂O₆ + 6 O₂ --> 6 CO₂ + 6 H₂O + energy

The term energy in the product side means that energy is conserved because it is being released due to the the glucose and oxygen (reactant side) have more energy stored in their bonds than the energy needed for the formation of carbon dioxide and water, so that excess of energy is released to form energy/ATP.

<u>Summarizing:</u>

  • The energy on the product side added to the energy of carbon dioxide and water equals the energy of the glucose and oxygen and the final balance is:

  • ∑ Energy of the reactants = ∑energy of the products + released energy, supporting the law of conservation of energy.
5 0
3 years ago
Which definition best describes the term activation energy?
dalvyx [7]

Answer:

B

Explanation:

bshdiidididjdjjdididid

4 0
3 years ago
Which formula can be used to find velocity if kinetic energy and mass are known?
astraxan [27]

Answer:

v =  \sqrt{ \frac{2ke}{m} }

option D is the correct option.

Here,

If an object of mass 'm' moving with a velocity'v' then,

kinetic \: energy =  \frac{1}{2} m {v}^{2}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:    {v}^{2}  =  \frac{2ke}{m}  \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  {v}^{2}  =  \sqrt{ \frac{2ke}{m} }

hope this helps...

Good luck on your assignment..

5 0
3 years ago
g The decomposition reaction of A to B is a first-order reaction with a half-life of 2.42×103 seconds: A → 2B If the initial con
Tanzania [10]

Answer:

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

Explanation:

The equation used to calculate the constant for first order kinetics:

t_{1/2}=\frac{0.693}{k}} .....(1)

Rate law expression for first order kinetics is given by the equation:

t=\frac{2.303}{k}\log\frac{[A_o]}{[A]} ......(2)

where,  

k = rate constant

t_{1/2} =Half life of the reaction = 2.42\times 10^3 s

t = time taken for decay process = ?

[A_o] = initial amount of the reactant = 0.163 M

[A] = amount left after time t =  66.8% of [A_o]

[A]=\frac{66.8}{100}\times 0.163 M=0.108884 M

k=\frac{0.693}{2.42\times 10^3 s}

t=\frac{2.303}{\frac{0.693}{2.42\times 10^3 s}}\log\frac{0.163 M}{0.108884 M}

t = 1,409.19 s

1 minute = 60 sec

t=\frac{1,409.19 }{60} min=23.49 min

In 23.49 minutes the concentration of A to be 66.8% of the initial concentration.

6 0
3 years ago
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