1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Luden [163]
2 years ago
5

Plzzzzzzzzzzzzzz answer fast

Chemistry
2 answers:
vfiekz [6]2 years ago
8 0

Answer:

Welding and computer chips

Vlad1618 [11]2 years ago
7 0

Answer:

computer chip,welding

You might be interested in
The element carbon exists in several different forms. Pure carbon can be found in the form of diamonds, coal, and the graphite i
UNO [17]

Answer:

B) All carbon atoms have 6 neutrons.

Explanation:

The false statement from the given choices is that all carbon atoms have 6 neutrons.

There is a phenomenon called isotopy in chemistry.

Isotopy is the existence of two or more atoms of the same element having the same atomic number but different mass numbers due to the differences in the number of neutrons in their various nuclei.

  • These atoms of elements are called isotopes.
  • Carbon atoms generally have proton number of 6 which is the same as the atomic number.
  • As with all atoms, the mass number or atomic mass equals the number of protons and neutrons.

For the isotopes of carbon, their number of neutrons differs.

 For example:

            <em>¹²₆C                           ¹³₆C                        ¹⁴₆C</em>

The number of neutrons differs in the above isotopes.

 Number of neutrons = mass number - atomic number;

    ¹²₆C  , number of neutrons  = 12 - 6  = 6

      ¹³₆C, number of neutrons  = 13 - 6  = 7

       ¹⁴₆C, number of neutrons = 14 - 6  = 8

Therefore, based on the concept of isotopy, all carbon atoms do not have 6 neutrons.

7 0
2 years ago
Thorium-234 has a half-life of 24.1 days. How many grams of a 150 g sample would you have after 120.5 days?
chubhunter [2.5K]

Answer:

8.625 grams of a 150 g sample of Thorium-234  would be left after 120.5 days

Explanation:

The nuclear half life represents the time taken for the initial amount of sample  to reduce into half of its mass.

We have given that the half life of thorium-234 is 24.1 days. Then it takes 24.1 days for a Thorium-234 sample to reduced to half of its initial amount.

Initial amount of Thorium-234 available as per the question is 150 grams

So now  we start with 150 grams  of Thorium-234

150 \times \frac{1}{2}=24.1

75 \times \frac{1}{2} =48.2

34.5 \times \frac{1}{2} =72.3

17.25 \times \frac{1}{2} =96.4

8.625\times \frac{1}{2} =120.5

So after 120.5 days the amount of sample that remains is 8.625g

In simpler way , we can use the below formula to find the sample left

A=A_{0} \cdot \frac{1}{2^{n}}

Where

A_0  is the initial sample amount  

n = the number of half-lives that pass in a given period of time.

7 0
3 years ago
A particular power source creates electricity through the use of giant magnets that are rotated to create a flow of electrons. T
Sloan [31]
From the electric generator to electric outlets in homes
6 0
2 years ago
Read 2 more answers
One way of obtaining pure sodium carbonate is through the decomposition of the mineral trona, Na3(CO3)(HCO3)·2H2O. 2Na3(CO3)(HCO
zhenek [66]
Percentage yield = (actual yield / theoretical yield) x 100%

The balanced equation for the decomposition is,
 2Na₃(CO₃)(HCO₃)·2H₂O(s) → 3Na₂CO₃(s) + CO₂(g) + 5H₂<span>O(g)

The stoichiometric ratio between </span>Na₃(CO₃)(HCO₃)·2H₂O(s)  and Na₂CO₃(s) is 2 : 3

The decomposed mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 1000 kg
                                                                                     = 1000 x 10³ g

Molar mass of Na₃(CO₃)(HCO₃)·2H₂O(s) = 226 g mol⁻¹
moles of Na₃(CO₃)(HCO₃)·2H₂O(s) = mass / molar mass
                                                         = 1000 x 10³ g / 226 g mol⁻¹
                                                         = 4424.78 mol

Hence, moles of Na₂CO₃ formed = 4424.78 mol x \frac{3}{2}
                                                     = 6637.17 mol

Molar mass of Na₂CO₃ = 106 g mol⁻¹

Hence, mass of Na₂CO₃ = 6637.17 mol x 106 g mol⁻¹
                                        = 703540.02 g
                                        = 703.540 kg

Hence, the theoretical yield of Na₂CO₃ =  703.540 kg
Actual yield of Na₂CO₃ = 650 kg

Percentage yield = (650 kg / 703.540 kg) x 100%
                            = 92.34%
7 0
3 years ago
An analysis of physical, chemical and microscopic properties of urine is called?​
oksano4ka [1.4K]

Answer:

urinalysis

Explanation:

5 0
3 years ago
Read 2 more answers
Other questions:
  • Describe the oceans and explain how the water cycle affects the salinity of the ocean?
    6·1 answer
  • ) how much of the primary standard benzoic acid (fm 122.12, density 1.27 g/ml) should you weigh out to obtain a 100.0 mm aqueous
    14·1 answer
  • What is the threshold frequency ν0 of cesium?
    11·1 answer
  • Which quantity is used to generate the error bars on a graph?
    11·1 answer
  • The structures within the cytoplasm of a eukaryotic cell is what
    8·1 answer
  • A primary purpose of conducting a hazardous materials exercise is to find out:
    9·1 answer
  • A gas occupies 18.5L at stp. what volume will it occupy at 735 torr and 57°c?
    13·1 answer
  • 1. MgCO,→ MgO +Co, is an example of a
    11·1 answer
  • Circle the letter of cach sentence that is true about silica.
    7·2 answers
  • A mixture of amino acids (written as M) was tested against five known amino acids (written as 1 to 5) and the chromatogram was m
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!