Answer:
The correct option is;
a. 255.0 g
Explanation:
The given information are;
Mass of propane, C₃H₈ in the combustion reaction = 156.06 g
The equation of the combustion reaction is C₃H₈ + 5O₂ → 3CO₂ + 4H₂O
From the balanced chemical equation of the reaction, we have;
One mole of propane, C₃H₈ reacts with five moles oxygen gas, O₂, to form three moles of carbon dioxide, CO₂, and four moles of water, H₂O
The molar mass of propane gas = 44.1 g/mol
The number of moles, n, of propane gas = Mass of propane gas/(Molar mass of propane gas) = 156.06/44.1 = 3.54 moles
Given that one mole of propane gas produces 4 moles of water molecule (steam) H₂O, 3.54 moles of propane gas will produce 4×3.54 = 14.16 moles of (steam) H₂O
The mass of one mole of H₂O = 18.01528 g/mol
The mass of 14.16 moles of H₂O = 14.16 × 18.01528 = 255.0 g
The mass of H₂O produced = 255.0 g
