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GaryK [48]
4 years ago
10

C6H12O6 + 6 O2 --> 6 CO2 + 6 H2O + energy In the reaction listed above, 1 molecule of glucose reacts with 6 molecules of oxyg

en to form 6 molecules of carbon dioxide, 6 molecules of water, and release energy. The law of conservation of energy is supported by this reaction equation because Question 1 options: the same kinds of elements are present both at the start and the end of the reaction there are more molecules at the end of the reaction than at the beginning energy present in the glucose and oxygen that is not needed for the formation of carbon dioxide and water is released to form energy/ATP. the number of carbon atoms, hydrogen atoms, and oxygen atoms is the same at the start and end of the reaction
Chemistry
1 answer:
kirill115 [55]4 years ago
5 0

Answer:

  • Third choice:<em> energy present in the glucose and oxygen that is not needed for the formation of carbon dioxide and water is released to form energy/ATP.</em>

Explanation:

<u>1) Chemical equation (given):</u>

  • C₆H₁₂O₆ + 6 O₂ --> 6 CO₂ + 6 H₂O + energy

<u>2) Chemical potential energy:</u>

Each compound stores chemical potential energy.  This energy is stored in the chemical bonds.

Due to every substance has its own unique chemical potential energy, when a chemical reaction takes plase, yielding to the change of some substances, some energy is absorbed (when bonds are formed) and some energy is released (when bonds are broken).

<u>3) Conservation of energy:</u>

Then, if the sum of the bond energies of the final products is less than the sum of the bond energies of the reactants, the<em> law of conservation of energy</em> rules that the difference between the total energies of the products and reactants must be released to the surroundings.

That is what is happening in the given reaction:

  • C₆H₁₂O₆ + 6 O₂ --> 6 CO₂ + 6 H₂O + energy

The term energy in the product side means that energy is conserved because it is being released due to the the glucose and oxygen (reactant side) have more energy stored in their bonds than the energy needed for the formation of carbon dioxide and water, so that excess of energy is released to form energy/ATP.

<u>Summarizing:</u>

  • The energy on the product side added to the energy of carbon dioxide and water equals the energy of the glucose and oxygen and the final balance is:

  • ∑ Energy of the reactants = ∑energy of the products + released energy, supporting the law of conservation of energy.
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What is the SI unit used to measure weight?
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Methane burns in the presence of oxygen to form carbon dioxide and water.
wlad13 [49]

Answer:

= 9.28 g CO₂

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Use molar ratio to find moles of CO₂

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5 0
3 years ago
For the following reaction, 6.94 grams of water are mixed with excess sulfur dioxide . Assume that the percent yield of sulfurou
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<h3>Answer:</h3>

#a. Theoretical yield = 31.6 g

#b. Actual yield = 25.72 g

<h3>Explanation:</h3>

The equation for the reaction between sulfur dioxide and water to form sulfurous acid is given by the equation;

SO₂(g) + H₂O(l) → H₂SO₃(aq)

The percent yield of H₂SO₃ is 81.4%

Mass of water that reacted is 6.94 g

#a. To get the theoretical yield of H₂SO₃ we need to follow the following steps

Step 1: Calculate the moles of water

Molar mass of water = 18.02 g/mol

Mass of water = 6.94 g

But, moles = Mass/molar mass

Moles of water = 6.94 g ÷ 18.02 g/mol

                        = 0.385 mol

Step 2: Calculate moles of H₂SO₃

From the equation, the mole ratio of water to H₂SO₃ is 1 : 1

Therefore, moles of water = moles of H₂SO₃

Hence, moles of H₂SO₃ = 0.385 mol

Step 3: Theoretical mass of H₂SO₃

Mass = moles × Molar mass

Molar mass of H₂SO₃ = 82.08 g/mol

Number of moles of H₂SO₃ = 0.385 mol

Therefore;

Theoretical mass of H₂SO₃ = 0.385 mol ×  82.08 g/mol

                                             = 31.60 g

Thus, the theoretical yield of H₂SO₃ is 31.6 g

<h3>#b. Calculating the actual yield</h3>

We need to calculate the actual yield

Percent yield of H₂SO₃ is 81.4%

Theoretical yield is 31.60 g

But; Percent yield = (Actual yield/theoretical yield)×100

Therefore;

Actual yield = Percent yield × theoretical yield)÷ 100

                   = (81.4 % × 31.6) ÷ 100

                  = 25.72 g

The percent yield of H₂SO₃ is 25.72 g

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