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inna [77]
3 years ago
7

Factorise fully p^3 + p^2

Mathematics
1 answer:
nikklg [1K]3 years ago
3 0

Answer:

\huge\boxed{p^3+p^2=p^2(p+1)}

Step-by-step explanation:

p^3+p^2\\\\p^3=p^{2+1}=p^2\cdot p\\\\p^3+p^2=p^2\cdot p+p^2\cdot1=p^2(p+1)

Used:

a^n\cdot a^m=a^{n+m}\\\\\text{distributive property}:\ a(b+c)=ab+ac

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suzy had 10L of water. She wanted to pour an equal amount of water into 5 thermoses. How many liters did she pour into each ther
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She poured 2L into each.

10 / 5 = 2
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3 years ago
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What is 9.65+0.4, 16.058- 1.2
gogolik [260]

Answer:

Step-by-step explanation:

9.65+0.4=10.05

16.058-1.2=14.858

4 0
1 year ago
The length of human pregnancies from conception to birth follows a distribution with mean 266 days and standard deviation 15 day
Katena32 [7]

Answer:

a) 81.5%

b) 95%

c) 75%

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 266 days

Standard Deviation, σ = 15 days

We are given that the distribution of  length of human pregnancies is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(between 236 and 281 days)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{281-266}{15})\\\\= P(-2 \leq z \leq 1)\\\\= P(z \leq 1) - P(z < -2)\\= 0.838 - 0.023 = 0.815 = 81.5\%

b) a) P(last between 236 and 296)

P(236 \leq x \leq 281)\\\\= P(\displaystyle\frac{236 - 266}{15} \leq z \leq \displaystyle\frac{296-266}{15})\\\\= P(-2 \leq z \leq 2)\\\\= P(z \leq 2) - P(z < -2)\\= 0.973 - 0.023 = 0.95 = 95\%

c) If the data is not normally distributed.

Then, according to Chebyshev's theorem, at least 1-\dfrac{1}{k^2}  data lies within k standard deviation of mean.

For k = 2

1-\dfrac{1}{(2)^2} = 75\%

Atleast 75% of data lies within two standard deviation for a non normal data.

Thus, atleast 75% of pregnancies last between 236 and 296 days approximately.

7 0
3 years ago
How do i get the median of a set of numbers?
yarga [219]

Answer:

first, arrange the numbers then classify the number into two like if there are 7 numbers classify into three then the middle one will be the median

4 0
3 years ago
Rewrite each fraction in simplest form using the GCF of the numerator and denominator.
Elanso [62]

Answer:

\sf 6. \quad \dfrac{7}{10}

\sf 7. \quad \dfrac{5}{17}

Step-by-step explanation:

<h3><u>Question 6</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

  • 42 = 2 × 3 × 7
  • 60 = 2 × 2 × 3 × 5

42 and 60 share one 2 and one 3 in common.

Multiply them together to get the GCF:  2 × 3 = 6.

Therefore, 6 is the GCF of 42 and 60.

Divide the numerator and the denominator by the found GCF:

\implies \sf \dfrac{42 \div 6}{60 \div 6}=\dfrac{7}{10}

<h3><u>Question 7</u></h3>

To find the greatest common factor (GCF), first list the prime factors of each number:

  • 80 = 2 × 2 × 2 × 2 × 5
  • 272 = 2 × 2 × 2 × 2 × 17

80 and 272 share four 2s in common.

Multiply them together to get the GCF:  2 × 2 × 2 × 2 = 16.

Therefore, 16 is the GCF of 80 and 272.

Divide the numerator and the denominator by the found GCF:

\implies \sf \dfrac{80 \div 16}{272 \div 16}=\dfrac{5}{17}

5 0
1 year ago
Read 2 more answers
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