Answer:
The hypotenuse of a right triangle is 4m longer than the shorter leg and 2m longer than the longer leg. What are the lengths of the sides?
Just for variety, consider the hypotenuse = h, the short leg h-4 and the long leg h-2.
c^2 = a^2 + b^2; so h^2 = (h-4)^2 + (h-2)^2; h^2 = h^2 - 8h + 16 +h^2 -4h +4;
h^2 -12h +20 = 0 factors to (h - 10)(h - 2) = 0 so h = 2 or h = 10
Since (h - 2) = (2 - 2) = 0 and a triangle cannot have a side of zero length, 10 is the length of the hypotenuse.
h^2 = (h-4)^2 + (h-2); 10^2 = (10-4)^2 + (10-2); (10)^2 = (6)^2 + (8)
The hypotenuse is 10 cm, short leg 6 cm and long leg 8 cm.
Answer:
D. 2
Step-by-step explanation:
soh cah toa rule
sine equals opposite over hypotenuse,
cosine equals adjacent over hypotenuse, and
tangent equals opposite over adjacent
csc is 1/sin which is hypotenuse over opposite
if csc is -√5/2 then
hypotenuse is -√5
opposite is 2
3rd quadrant on a graph is bottom left
both x and y values are negative
hypotenuse means its a triangle
pythagorean theorem
a^2 + b^2 = c^2
a^2 + 2^2 = (-√5)^2
a^2 + 4 = 5
a = 1 = adjacent
tangent equals opposite over adjacent
tan is 2 / 1 which is 2
third quadrant means it's still positive
because tan is positive in quadrant 3
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Answer:
B: 2 1/7
Step-by-step explanation:
15 divided by 7 = 2 1/7
Answer is: B
Step-by-step explanation: correct answer is B
b
2
−a
2
Given, acotθ+bcscθ=p
bcotθ+acscθ=q
⇒p
2
−q
2
=(p−q)(p+q)
=[acotθ+bcscθ−bcotθ−acscθ][acotθ+bcscθ+bcotθ+acscθ]
=[cotθ(a−b)−cscθ(a−b)][cotθ(a+b)+cscθ(a+b)]
=(a−b)(cotθ−cscθ)(a+b)(cotθ+cscθ)
=(a
2
−b
2
)(cot
2
θ−csc
2
θ)
=(−1)(a
2
−b
2
)[∵csc
2
θ−cot
2
θ=1]
=(b
2
−a
2
)
Answer:
Step-by-step explanation:
This question is asking you to find the value of y when x = -4. If you locate the x value of -4, y = -10 here. Therefore, f(-4) = -10 and in coordinate form, (-4, -10).
