Answer:
168 is the answer if i m not wrong.I took the LCM.
(16-x²)+(4-x) or (-x²+16)+(-x+4)
Combine like terms
(-x²+20-x) or (-x²-x+20)
Answer:
Step-by-step explanation:
<u>Prime factors of 2100 are:</u>
<u>The single-digit divisors are:</u>
- 1, 2, 3, 2*2= 4, 5, 2*3= 6, 7
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<u>Another solution is you divide 2100 by all numbers 1 through 9 and list those divisible:</u>
- 2100/1 = 2100, yes
- 2100/2 = 1050, yes
- 2100/3 = 700, yes
- 2100/4 = 525, yes
- 2100/5 = 420, yes
- 2100/6 = 350, yes
- 2100/7 = 300, yes
- 2100/8 = 262.5, no
- 2100/9 = 233.33, no
So all the numbers from 1 to 7
Answer:
The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.
Step-by-step explanation:
We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.
The probability of k online retail orders that turn out to be fraudulent in the sample is:

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:
![P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483](https://tex.z-dn.net/?f=P%28x%5Cgeq2%29%3D1-%5BP%28x%3D0%29%2BP%28x%3D1%29%5D%5C%5C%5C%5C%5C%5CP%28x%3D0%29%3D%5Cdbinom%7B20%7D%7B0%7D%5Ccdot0.08%5E%7B0%7D%5Ccdot0.92%5E%7B20%7D%3D1%5Ccdot1%5Ccdot0.189%3D0.189%5C%5C%5C%5C%5C%5CP%28x%3D1%29%3D%5Cdbinom%7B20%7D%7B1%7D%5Ccdot0.08%5E%7B1%7D%5Ccdot0.92%5E%7B19%7D%3D20%5Ccdot0.08%5Ccdot0.205%3D0.328%5C%5C%5C%5C%5C%5C%5C%5CP%28x%5Cgeq2%29%3D1-%5B0.189%2B0.328%5D%5C%5C%5C%5CP%28x%5Cgeq2%29%3D1-0.517%3D0.483)
The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.
Answer:
11
Step-by-step explanation
because i added and subtrcted and minus