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DiKsa [7]
4 years ago
12

Solve for h. Round to the tenths place. Show your work.

Mathematics
1 answer:
Vinvika [58]4 years ago
4 0
You can use the Pythagorean theorem for this problem.
a^2 + b^2 = c^2
a^2 + 5^2 = 10^2
a^2 + 25 = 100
a^2 = 75
a = 8.66

h = 8.7

Hope this helps =)
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Find three consecutive even integers such that six times the sum of the first and the third is twenty - four greater than eleven
dedylja [7]

Answer:

1st = 22

2nd = 24

3rd = 26

Step-by-step explanation:

1st = x

2nd = x +2

3rd = x + 4

6(x + x + 4) = 24 + 11(x + 2)

6(2x + 4) = 24 + 11x + 22

12x + 24 = 46 + 11x

x + 24 = 46

x = 22

x + 2 = 24

x + 4 = 26

8 0
3 years ago
First answer gets brainliest (worth 10 points) pls answer asap
AysviL [449]

Answer:

B

Step-by-step explanation:

(-2) ^-3 • (-2) ^4 = -2

-2^1 = -2

Hope this helps

6 0
3 years ago
What is 4,231 divided by 7?
shusha [124]
I think it is 604.4285714285714
3 0
4 years ago
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Prajna is listing squares of two-digit numbers in such a way that the digit in their units place is 6.
dem82 [27]

Answer:

2 (option B)

Question:

Prajna is listing squares of two-digit numbers in such a way that the digit in their units place is 6.

How many numbers should he have listed?

a) 9 b) 2 c)18 d) 20

Step-by-step explanation:

We would find the perfect squares that are two digit numbers

For two digit perfect squares:

Largest two digit number= 81 = 9²

Smallest two digit number= 16 = 4²

Total Two digit number perfect squares = Highest number - lowest number + 1

= 9-4+1 = 6

There are 6 two digit perfect squares

Next, we have to find how many of them have 6 in their units place.

The rule to be applied: If a number has 4 or 6 in the unit place, then its square has 6 in the units place.

Following this, the possibilities are 4², 6².

We have two of such numbers.

Therefore, he would have listed 2 numbers.

6 0
3 years ago
14 divided by negative 7/5
bixtya [17]

Answer:

-10

Step-by-step explanation:

14 / -7/5

14/1 /-7/5

14/1 *-5/7= -70/7=-10

7 0
4 years ago
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