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Jlenok [28]
3 years ago
5

4kmno4=2k2o+4mno+4o2 does this support the law of conservation of mass

Chemistry
1 answer:
Aleks04 [339]3 years ago
3 0

Answer:

U should do like this... It's true

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Laughing gas (nitrous oxide, N20) is some-
alukav5142 [94]

Answer: 109.2g

Explanation:

1 mole N2O = 34 g

46.4g = 46.4/34 moles = 1.365 moles

1 mole N2O is from 1 mole NH4NO3

1.365 moles NH4NO3 = 1.365*80g = 109.2g

6 0
3 years ago
At 23°C, 85.0 grams of NaNO3(s) are dissolved in 100. grams of H2O(l).
Alenkinab [10]

5g

Anything between 4 and 6 is ok.

8 0
3 years ago
A sample of CO2 weighing 86.34g contains how many molecules?
irakobra [83]

Answer:

1.181 × 10²⁴ molecules CO₂

General Formulas and Concepts:

<u>Chemistry - Atomic Structure</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

<u>Step 1: Define</u>

86.34 g CO₂

<u>Step 2: Identify Conversion</u>

Avogadro's Number

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CO₂ - 12.01 + 2(16.00) = 44.01 g/mol

<u>Step 3: Convert</u>

<u />86.34 \ g \ CO_2(\frac{1 \ mol \ CO_2}{44.01 \ g \ CO_2} )(\frac{6.022 \cdot 10^{23} \ molecules \ CO_2}{1 \ mol \ CO_2} ) = 1.18141 × 10²⁴ molecules CO₂

<u>Step 4: Check</u>

<em>We are given 4 sig figs. Follow sig fig rules and round.</em>

1.18141 × 10²⁴ molecules CO₂ ≈ 1.181 × 10²⁴ molecules CO₂

4 0
3 years ago
Acids have a high concentration of ...
GrogVix [38]

Answer:

Acids have a high concentration of [H⁺] ions

Explanation:

In order to know about the acids, a solution is acidic when pH < 7

As pH is lower than 7, the pOH > 7

When pH = 7, solution is neutral

When pH is greater than 7, solution is basic

pH = - log [H⁺]

pOH = - log [OH⁻]

Imagine a solution of pure HCl 0.2 M

HCl → H⁺ + OH⁻

[H⁺] = 0.2 M → pH = - log 0.2 → 0.69

pH + pOH = 14

pOH = 14 - 0.69 = 13.31

10^-pOH = [OH⁻] → 10⁻¹³°³¹ = 4.89ₓ10⁻¹⁴

In conclussion [H⁺] > [OH⁻]

8 0
4 years ago
How many moles are in 68 grams of copper (ll) hydroxide, Cu(OH)2
Sveta_85 [38]
Molar mass Cu(OH)2 => 97.561 g/mol

Therefore:

1 mole Cu(OH)2 ------------ 97.561 g
? moles Cu(OH)2 ----------- 68 g

 = 68 x 1 / 97.561

=  68 / 97.561

= 0.696 moles of Cu(OH)2
4 0
3 years ago
Read 2 more answers
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