Question

How many moles are in 68 grams of copper (ll) hydroxide, Cu(OH)2

Answer 1

Answer: The moles of copper (I) hydroxide are 0.70 moles.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

We are given:

Given mass of copper (I) hydroxide = 68 g

Molar mass of copper (I) hydroxide = 97.6 g/mol

Putting values in above equation, we get:

$\text{Moles of copper (I) hydroxide}=\frac{68g}{97.6g/mol}=0.70mol$

Hence, the moles of copper (I) hydroxide are 0.70 moles.

Answer 2

Molar mass Cu(OH)2 => 97.561 g/mol

Therefore:

1 mole Cu(OH)2 ------------ 97.561 g
? moles Cu(OH)2 ----------- 68 g

 = 68 x 1 / 97.561

=  68 / 97.561

= 0.696 moles of Cu(OH)2