Question

If 3.25 mol of Ar occupies 100. L at a particular temp and pressure, what volume does

Answer 1

Answer:

435.38 L

Explanation:

From the question,

Applying ideal gas equation,

PV = nRT................... Equation 1

Where P = Pressure, V = Volume, n = number of moles, R = molar gas constant, T = Temperature.

Since Temperature and Pressure were constant,

V ∝ n

V/n = V'/n'.................... Equation 2

Where V and V'  = the initial and final Volume of Ar respectively, n and n'  = the initial and final moles of Ar respectively

make V' the subject of the equation

V' = Vn'/n............... Equation 3

Given: V = 100 L, n = 3.25 mol, n' = 14.15

Substitute into equation 3

V' = (100×14.14)/3.25

V' = 435.38 L